POJ 3686 The Windy's 最小费用最大流

每个工厂拆成N个工厂,费用分别为1~N倍原费用。

//#pragma comment(linker, "/STACK:1024000000,1024000000")
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<algorithm>
#include<iostream>
#include<sstream>
#include<cmath>
#include<climits>
#include<string>
#include<map>
#include<queue>
#include<vector>
#include<stack>
#include<set>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int> pii;
#define pb(a) push(a)
#define INF 0x1f1f1f1f
#define lson idx<<1,l,mid
#define rson idx<<1|1,mid+1,r
#define PI 3.1415926535898
template<class T> T min(const T& a,const T& b,const T& c) {
return min(min(a,b),min(a,c));
}
template<class T> T max(const T& a,const T& b,const T& c) {
return max(max(a,b),max(a,c));
}
void debug() {
#ifdef ONLINE_JUDGE
#else
freopen("in.txt","r",stdin);
// freopen("d:\\out1.txt","w",stdout);
#endif
}
int getch() {
int ch;
while((ch=getchar())!=EOF) {
if(ch!=' '&&ch!='\n')return ch;
}
return EOF;
} const int maxn = ;
int N, M;
int cost[maxn][maxn]; void Input()
{
scanf("%d%d", &N, &M);
for(int i = ; i <= N; i++)
for(int j = ; j <= M; j++)
scanf("%d", &cost[i][j]);
} struct Edge
{
int from, to, cost, cap;
};
const int maxv = maxn * maxn + maxn;
vector<int> g[maxv];
vector<Edge> edge;
int n,s,t; void add(int from, int to, int cost, int cap)
{
edge.push_back((Edge){from, to, cost, cap});
g[from].push_back(edge.size() - );
edge.push_back((Edge){to, from, -cost, });
g[to].push_back(edge.size() - );
} void init()
{
for(int i = ; i <= n; i++)
g[i].clear();
edge.clear();
} void construct()
{
n = N + N * M + ;
s = n - ;
t = n;
init(); for(int i = ; i <= N; i++)
add(s, i, , );
for(int k = ; k <= N; k++)
{
for(int j = ; j <= M; j++)
{
int id = N + (k - ) * M + j;
add(id, t, , );
for(int i = ; i <= N; i++)
add(i, id, k * cost[i][j], );
}
}
} int d[maxv];
int inq[maxv];
int road[maxv];
int SPFA()
{
memset(d, INF, sizeof(d));
memset(inq, , sizeof(inq));
queue<int> q;
q.push(s);
d[s] = ;
road[s] = -; while(!q.empty())
{
int u = q.front(); q.pop();
inq[u] = false; for(int i = ; i < g[u].size(); i++)
{
Edge &e = edge[g[u][i]];
if(e.cap > && d[u] + e.cost < d[e.to])
{
d[e.to] = d[u] + e.cost;
road[e.to] = g[u][i];
if(!inq[e.to])
{
inq[e.to] = true;
q.push(e.to);
}
}
}
}
return d[t] != INF;
}
int MCMF()
{
int cost = ;
while(SPFA())
{
cost += d[t];
for(int e = road[t]; e != -; e = road[edge[e].from])
{
edge[e].cap -= ;
edge[e^].cap += ;
}
}
return cost;
}
int main()
{
debug();
int t;
scanf("%d", &t);
for(int ca = ; ca <= t; ca++)
{
Input();
construct();
printf("%.6f\n", MCMF() * 1.0 / N);
}
return ;
}
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