测试数据：

SQL> select * from sscore;

NAME       SCORE

---------- -----

aa            99

bb            56

cc            56

dd            77

ee            78

ff            76

gg            78

ff            50

8 rows selected

针对以上表，需要按成绩进行排序，从而取得名次信息：

实现方法一：分析函数

SQL> select name,score,dense_rank() over(order by score desc) as rk

2  from sscore;

NAME       SCORE         RK

---------- ----- ----------

aa            99          1

gg            78          2

ee            78          2

dd            77          3

ff            76          4

cc            56          5

bb            56          5

ff            50          6

8 rows selected

实现方法二：普通SQL：

SQL> select a.name,

2         a.score,

3         (select count(distinct score) from sscore b where a.score <= b.score) as rk

4    from sscore a

5   order by rk asc;

NAME       SCORE         RK

---------- ----- ----------

aa            99          1

gg            78          2

ee            78          2

dd            77          3

ff            76          4

cc            56          5

bb            56          5

ff            50          6

8 rows selected