前言:
上次写了查询5天之内过生日的同事中的跨年问题的解决过程,网址为:http://blog.csdn.net/mchdba/article/details/38952033 ,当中漏了一个闰年2月29日生日的细节问题,如今补充一下这个问题的处理过程:
5,补充闰年推断
有朋友提醒,闰年2月29日生日的话,可能查询不到,想到确实没有考虑到这个特殊的日期。
5.1,准备測试数据SQL,包括1980-02-29这一天生日的朋友。
INSERT INTO ali_users SELECT 'Jeff','1980-02-29','13998786549'
UNION ALL SELECT 'WeiYa','1980-02-28','13998786549'
UNION ALL SELECT 'XiaoTeng','1980-03-01','13998786549'
UNION ALL SELECT 'HeSheng','1980-03-02','13998786549'
UNION ALL SELECT 'JingPan','1980-03-03','13998786549'
UNION ALL SELECT 'WuHong','1986-03-04','13998786549';
5.2,录入測试数据
- mysql> use test;
- Reading table information for completion of table and column names
- You can turn off this feature to get a quicker startup with -A
- Database changed
- mysql> INSERT INTO ali_users SELECT \'Jeff\',\'1980-02-29\',\'13998786549\' UNION ALL SELECT \'XiaoTeng\',\'1980-03-01\',\'13998786549\'
- -> UNION ALL SELECT \'HeSheng\',\'1980-03-02\',\'13998786549\'
- -> UNION ALL SELECT \'JingPan\',\'1980-03-03\',\'13998786549\'
- -> UNION ALL SELECT \'WuHong\',\'1986-03-04\',\'13998786549\';
- Query OK, 5 rows affected (0.00 sec)
- Records: 5 Duplicates: 0 Warnings: 0
- mysql>
5.3,运行原来的旧版本号的SQL查询检查结果
把Step#2中的SQL的NOW()改成'2014-02-28 00:10:10'来进行測试,确实没有包括2月29日生日的同事,例如以下所看到的:
- mysql> SELECT * FROM ali_users WHERE
- -> DATEDIFF(CAST(CONCAT(YEAR(\'2014-02-28 00:10:10\'),DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(DATE_FORMAT(\'2014-02-28 00:10:10\',\'%y-%m-%d\') AS DATE)) BETWEEN 0 AND 4
- -> OR/* or后面的是捎带解决跨年问题*/
- -> DATEDIFF(CAST(CONCAT(YEAR(\'2014-02-28 00:10:10\')+1,DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(DATE_FORMAT(\'2014-02-28 00:10:10\',\'%y-%m-%d\') AS DATE)) BETWEEN 0 AND 4
- -> ;
- +----------+------------+-------------+
- | username | birthday | iphone |
- +----------+------------+-------------+
- | XiaoTeng | 1980-03-01 | 13998786549 |
- | HeSheng | 1980-03-02 | 13998786549 |
- | JingPan | 1980-03-03 | 13998786549 |
- | WuHong | 1986-03-04 | 13998786549 |
- +----------+------------+-------------+
- 4 rows in set, 2 warnings (0.00 sec)
- mysql>
5.4,先建立一个存储函数f_isleap_year推断当年年份是否是闰年
5.4.1 准备推断是否闰年的SQL
- DELIMITER $$
- USE `test`$$
- DROP FUNCTION IF EXISTS `f_not_leap_year`$$
- CREATE FUNCTION `f_not_leap_year`(p_year BIGINT) RETURNS BOOLEAN
- BEGIN
- /*是闰年则返回0(false),不是闰年则返回1(true)*/
- DECLARE v_flag INT DEFAULT 0;
- /*①、普通年能被4整除且不能被100整除的为闰年。(如2004年就是闰年,1901年不是闰年)*/
- IF (p_year%4)=0 AND (p_year%100)>0 THEN
- SET v_flag=0;
- /*②、世纪年能被400整除的是闰年。(如2000年是闰年,1900年不是闰年) */
- ELSEIF (p_year%400)=0 THEN
- SET v_flag=0;
- /*③、对于数值非常大的年份,这年假设能整除3200,而且能整除172800则是闰年。如172800年是闰年,
- 86400年不是闰年(由于尽管能整除3200,但不能整除172800)(此按一回归年365天5h48\'45.5\'\'计算)。
- */
- ELSEIF (p_year%3200)=0 AND (p_year%172800)=0 THEN
- SET v_flag=0;
- ELSE
- SET v_flag=1;
- END IF;
- RETURN v_flag;
- END$$
- DELIMITER ;
存储函数运行例如以下图所看到的:
5.4.2 准备SQL语句
- SELECT * FROM ali_users WHERE
- DATEDIFF(CAST(CONCAT(YEAR(NOW()),DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(DATE_FORMAT(NOW(),\'%y-%m-%d\') AS DATE)) BETWEEN 0 AND 4
- OR/* or后面的是捎带解决跨年问题*/
- DATEDIFF(CAST(CONCAT(YEAR(NOW())+1,DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(DATE_FORMAT(NOW(),\'%y-%m-%d\') AS DATE)) BETWEEN 0 AND 4
- OR /*补充闰年2月29日的生日问题*/
- (
- f_not_leap_year(YEAR(NOW()))
- AND DATE_FORMAT(birthday,\'-%m-%d\')=\'-02-29\'
- AND DATEDIFF(CAST(CONCAT(\'2000\',DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(CONCAT(\'2000\',DATE_FORMAT(NOW(),\'-%m-%d\')) AS DATE))
- BETWEEN 0 AND 4
- );
5.4.3 在非闰年的时候,验证闰年2月29日生日,选择2014年非闰年測试
把Step#2中的SQL的NOW()改成'2014-02-28 00:10:10'来进行測试,SQL例如以下所看到的:
SELECT * FROM ali_users WHERE
DATEDIFF(CAST(CONCAT(YEAR('2014-02-28 00:10:10'),DATE_FORMAT(birthday,'-%m-%d'))AS DATE),CAST(DATE_FORMAT('2014-02-28 00:10:10','%y-%m-%d') AS DATE)) BETWEEN 0 AND 4
OR/* or后面的是捎带解决跨年问题*/
DATEDIFF(CAST(CONCAT(YEAR('2014-02-28 00:10:10')+1,DATE_FORMAT(birthday,'-%m-%d'))AS DATE),CAST(DATE_FORMAT('2014-02-28 00:10:10','%y-%m-%d') AS DATE)) BETWEEN 0 AND 4
OR /*补充闰年2月29日的生日方法*/
(
f_not_leap_year(YEAR('2014-02-28 00:10:10'))
AND DATE_FORMAT(birthday,'-%m-%d')='-02-29'
AND DATEDIFF(CAST(CONCAT('2000',DATE_FORMAT(birthday,'-%m-%d'))AS DATE),CAST(CONCAT('2000',DATE_FORMAT('2000-02-28 00:10:10','-%m-%d')) AS DATE))
BETWEEN 0 AND 4
);
运行SQL检验成果,假设当天是2014-02-28,看到已经有2月29日的生日的同事被记录进来了,事实上包括了2月28日、2月29日、3月1日、3月2日、3月3日、3月4日的生日的同事。
PS:由于2月29日在当年不存在,所以不算这5天之内的范畴,运行结果例如以下所看到的:
- mysql> SELECT * FROM ali_users WHERE
- -> DATEDIFF(CAST(CONCAT(YEAR(\'2014-02-28 00:10:10\'),DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(DATE_FORMAT(\'2014-02-28 00:10:10\',\'%y-%m-%d\') AS DATE)) BETWEEN 0 AND 4
- -> OR/* or后面的是捎带解决跨年问题*/
- -> DATEDIFF(CAST(CONCAT(YEAR(\'2014-02-28 00:10:10\')+1,DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(DATE_FORMAT(\'2014-02-28 00:10:10\',\'%y-%m-%d\') AS DATE)) BETWEEN 0 AND 4
- -> OR /*补充闰年2月29日的生日方法*/
- -> (
- -> f_not_leap_year(YEAR(\'2014-02-28 00:10:10\'))
- -> AND DATE_FORMAT(birthday,\'-%m-%d\')=\'-02-29\'
- -> AND DATEDIFF(CAST(CONCAT(\'2000\',DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(CONCAT(\'2000\',DATE_FORMAT(\'2000-02-28 00:10:10\',\'-%m-%d\')) AS DATE))
- -> BETWEEN 0 AND 4
- -> );
- +----------+------------+-------------+
- | username | birthday | iphone |
- +----------+------------+-------------+
- | Jeff | 1980-02-29 | 13998786549 |
- | XiaoTeng | 1980-03-01 | 13998786549 |
- | HeSheng | 1980-03-02 | 13998786549 |
- | JingPan | 1980-03-03 | 13998786549 |
- | WuHong | 1986-03-04 | 13998786549 |
- | WeiYa | 1980-02-28 | 13998786549 |
- +----------+------------+-------------+
- 6 rows in set, 2 warnings (0.00 sec)
- mysql>
5.4.4 在闰年的时候,验证闰年2月29日生日,选择2004年闰年測试
把Step#2中的SQL的NOW()改成'2004-02-28 00:10:10'来进行測试,SQL例如以下所看到的:
- SELECT * FROM ali_users WHERE
- DATEDIFF(CAST(CONCAT(YEAR(\'2004-02-28 00:10:10\'),DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(DATE_FORMAT(\'2004-02-28 00:10:10\',\'%y-%m-%d\') AS DATE)) BETWEEN 0 AND 4
- OR/* or后面的是捎带解决跨年问题*/
- DATEDIFF(CAST(CONCAT(YEAR(\'2004-02-28 00:10:10\')+1,DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(DATE_FORMAT(\'2004-02-28 00:10:10\',\'%y-%m-%d\') AS DATE)) BETWEEN 0 AND 4
- OR /*补充闰年2月29日的生日方法*/
- (
- f_not_leap_year(YEAR(\'2004-02-28 00:10:10\'))
- AND DATE_FORMAT(birthday,\'-%m-%d\')=\'-02-29\'
- AND DATEDIFF(CAST(CONCAT(\'2000\',DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(CONCAT(\'2000\',DATE_FORMAT(\'2004-02-28 00:10:10\',\'-%m-%d\')) ASDATE))
- BETWEEN 0 AND 4
- );
运行SQL检验成果,假设当天是2004-02-28,看到已经有2月29日的生日的同事被记录进来了,事实上包括了2月28日、2月29日、3月1日、3月2日、3月3日的生日的同事。
PS:由于2月29日在当年存在,所以算这5天之内的范畴,运行结果例如以下所看到的:
- mysql> SELECT * FROM ali_users WHERE
- -> DATEDIFF(CAST(CONCAT(YEAR(\'2004-02-28 00:10:10\'),DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(DATE_FORMAT(\'2004-02-28 00:10:10\',\'%y-%m-%d\') AS DATE)) BETWEEN 0 AND 4
- -> OR/* or后面的是捎带解决跨年问题*/
- -> DATEDIFF(CAST(CONCAT(YEAR(\'2004-02-28 00:10:10\')+1,DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(DATE_FORMAT(\'2004-02-28 00:10:10\',\'%y-%m-%d\') AS DATE)) BETWEEN 0 AND 4
- -> OR /*补充闰年2月29日的生日方法*/
- -> (
- -> f_not_leap_year(YEAR(\'2004-02-28 00:10:10\'))
- -> AND DATE_FORMAT(birthday,\'-%m-%d\')=\'-02-29\'
- -> AND DATEDIFF(CAST(CONCAT(\'2000\',DATE_FORMAT(birthday,\'-%m-%d\'))AS DATE),CAST(CONCAT(\'2000\',DATE_FORMAT(\'2004-02-28 00:10:10\',\'-%m-%d\')) AS DATE))
- -> BETWEEN 0 AND 4
- -> );
- +----------+------------+-------------+
- | username | birthday | iphone |
- +----------+------------+-------------+
- | Jeff | 1980-02-29 | 13998786549 |
- | XiaoTeng | 1980-03-01 | 13998786549 |
- | HeSheng | 1980-03-02 | 13998786549 |
- | JingPan | 1980-03-03 | 13998786549 |
- | WeiYa | 1980-02-28 | 13998786549 |
- +----------+------------+-------------+
- 5 rows in set (0.00 sec)
- mysql>