1 #define _for(i,a,b) for(int i = (a);i < (b);i ++) 2 class Solution 3 { 4 public: 5 int maxSumTwoNoOverlap(vector<int>& A, int L, int M) 6 { 7 vector<int> m1(A.size()),m2(A.size()); 8 m1[0] = m2[0] = 0; 9 _for(i,0,L) 10 m1[0] += A[i]; 11 _for(i,0,M) 12 m2[0] += A[i]; 13 14 _for(i,1,A.size()-L+1) 15 { 16 m1[i] = (m1[i-1]-A[i-1]+A[i+L-1]); 17 } 18 _for(i,1,A.size()-M+1) 19 { 20 m2[i] = (m2[i-1]-A[i-1]+A[i+M-1]); 21 } 22 int rnt = 0; 23 _for(i,0,A.size()-L+1) 24 { 25 int l1 = i,r1 = i+L-1; 26 _for(j,0,A.size()-M+1) 27 { 28 int l2 = j,r2 = j+M-1; 29 if(r2<l1 || l2>r1) 30 rnt = max(rnt,m1[i]+m2[j]); 31 } 32 } 33 return rnt; 34 } 35 };
Leetcode-1031 Maximum Sum of Two Non-Overlapping Subarrays(两个非重叠子数组的最大和)