C#中接口无法被xml序列化,提示不支持。百度和bing也搜不到,只好自己动手写了
原理上肯定支持,.Net自己的xml序列化有一个IXmlSerializable接口。
自行实现该接口,并取得实现改接口的类,再进行自定义的序列化处理即可。
using System.Collections; using System.Xml.Serialization; using System; using System.Xml; [XmlRoot("SerInterface"), Serializable] public class SerInterface<TInterface> : IXmlSerializable { public TInterface Source { get { return (TInterface)mSource; } } string mTypeName; object mSource; public SerInterface() { } public SerInterface(object interfaceObj) { this.mSource = interfaceObj; mTypeName = mSource.GetType().FullName; } public System.Xml.Schema.XmlSchema GetSchema() { return null; } public void ReadXml(XmlReader reader) { var typeSer = new XmlSerializer(typeof(string)); bool wasEmpty = reader.IsEmptyElement; reader.Read(); if (wasEmpty) return; while (reader.NodeType != XmlNodeType.EndElement) { reader.ReadStartElement("Type"); mTypeName = typeSer.Deserialize(reader) as string; reader.ReadEndElement(); var sourceSer = new XmlSerializer(Type.GetType(mTypeName)); reader.ReadStartElement("Object"); mSource = sourceSer.Deserialize(reader); reader.ReadEndElement(); reader.MoveToContent(); } reader.ReadEndElement(); } public void WriteXml(XmlWriter writer) { var typeSer = new XmlSerializer(typeof(string)); var sourceSer = new XmlSerializer(mSource.GetType()); writer.WriteStartElement("Type"); typeSer.Serialize(writer, mTypeName); writer.WriteEndElement(); writer.WriteStartElement("Object"); sourceSer.Serialize(writer, mSource); writer.WriteEndElement(); } }
使用:
//把接口嵌套 IXXX tmp = new Class1(); var serInterface = new SerInterface<IXXX>(tmp); //序列化 var xmlSer = new XmlSerializer(serInterface.GetType()); var writer = new MemoryStream(); xmlSer.Serialize(writer, serInterface); StreamReader sr = new StreamReader(writer); var serStr = Encoding.UTF8.GetString(writer.ToArray()); writer.Flush(); writer.Close(); sr.Close(); //反序列化 xmlSer = new XmlSerializer(typeof(SerInterface<IXXX>)); TextReader reader = new StringReader(serStr); var deSer = xmlSer.Deserialize(reader); //原始数据 var sourceInterfaceData = (deSer as SerInterface<IXXX>).Source;