Python 线程(二):简单锁实现线程同步

Python中有两种锁,一个锁是原始的锁(原语), 不可重入,而另一种锁则是可重入的锁即递归锁。而是thread模块中,只提供了不可重入的锁,而在threading中则提供这两种锁。

可重入:当一个线程拥有一个锁的使用权后,再次获取锁的使用权时,不会阻塞,会立马得到使用权,则原始锁的话,则不行,会阻塞。

方法一:thead的不可重入锁

  

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import thread
import time
 
lock = thread.allocate_lock()
 
def Count(id):
    global num;
 
    while True:
        lock.acquire()
        if num <= 10:
            print "Thread id is : %s     The num is %s\n" % (id, str(num))
            num = num + 1
        else:
            break
        lock.release()
    else:
        thread.exit_thread()
 
if __name__ == "__main__":
    num = 1
    thread.start_new_thread(Count, (‘A‘,))
    thread.start_new_thread(Count, (‘B‘,))
 
    time.sleep(5)

  

方法二:theading的Lock(不可重入锁)

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import threading
import time
 
lock = threading.Lock()
 
def Count(id):
    global num;
 
    while True:
        lock.acquire()
        if num <= 10:
 
            print "Thread id is : %s     The num is %s\n" % (id, str(num))
            num = num + 1
        else:
            break
        lock.release()
 
if __name__ == "__main__":
    num = 1
    t1 = threading.Thread(target=Count, args=(‘A‘, ))
    t2 = threading.Thread(target=Count, args=(‘B‘, ))
 
    t1.start()
    t2.start()
 
    time.sleep(5)

  方法三:threading的RLock(可重入)

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import threading
import time
 
lock = threading.RLock()
 
def CountNum(id):
    global num
     
    lock.acquire()
     
    if num <= 10:
        print "Thread id is : %s     The num is %s\n" % (id, str(num))
        num = num + 1
        CountNum(id)
 
    lock.release()
 
if __name__ == "__main__":
    num = 1
    t1 = threading.Thread(target=CountNum, args=(‘A‘))
 
    t1.start()
 
    time.sleep(5)

Python 线程(二):简单锁实现线程同步,布布扣,bubuko.com

Python 线程(二):简单锁实现线程同步

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