class Solution {
List<List<Integer>> result;
List<Integer> path;
public List<List<Integer>> allPathsSourceTarget(int[][] graph) {
path = new LinkedList<>();
result = new LinkedList<>();
path.add(0);
dfs(graph,0);
return result;
}
public void dfs(int[][] graph, int node){
//当前节点是最后一个节点
if (node==graph.length-1){
result.add(new LinkedList<>(path));
return;
}
// 循环该节点的各条路径
for (int index=0;index<graph[node].length;index++){
int nextNode = graph[node][index];
path.add(nextNode);
dfs(graph,nextNode);
path.removeLast();
}
}
}
class Solution {
public int numIslands(char[][] grid) {
int result = 0;
//遍历网格,找到岛屿(即:‘1’)
for (int i=0;i<grid.length;i++){
for (int j=0;j<grid[0].length;j++){
if (grid[i][j]=='1'){
result++;
dfs(grid,i,j);
}
}
}
return result;
}
// 将找到的一个岛屿“淹没”,同时对其相连的岛屿淹没,因为这属于同一片岛屿
public void dfs(char[][] grid, int i, int j){
if(i < 0 || i >= grid.length || j < 0 || j >= grid[0].length || grid[i][j] == '0') return;
grid[i][j] = '0';
dfs(grid,i-1,j);
dfs(grid,i+1,j);
dfs(grid,i,j-1);
dfs(grid,i,j+1);
}
}
class Solution {
public int numIslands(char[][] grid) {
if (grid == null || grid.length == 0) {
return 0;
}
int nr = grid.length;
int nc = grid[0].length;
int num_islands = 0;
for (int r = 0; r < nr; ++r) {
for (int c = 0; c < nc; ++c) {
if (grid[r][c] == '1') {
++num_islands;
grid[r][c] = '0';
Queue<Integer> neighbors = new LinkedList<>();
neighbors.add(r * nc + c);
while (!neighbors.isEmpty()) {
int id = neighbors.remove();
int row = id / nc;
int col = id % nc;
if (row - 1 >= 0 && grid[row-1][col] == '1') {
neighbors.add((row-1) * nc + col);
grid[row-1][col] = '0';
}
if (row + 1 < nr && grid[row+1][col] == '1') {
neighbors.add((row+1) * nc + col);
grid[row+1][col] = '0';
}
if (col - 1 >= 0 && grid[row][col-1] == '1') {
neighbors.add(row * nc + col-1);
grid[row][col-1] = '0';
}
if (col + 1 < nc && grid[row][col+1] == '1') {
neighbors.add(row * nc + col+1);
grid[row][col+1] = '0';
}
}
}
}
}
return num_islands;
}
}