【LeetCode】831. Masking Personal Information 解题报告（Python）
标签（空格分隔）： LeetCode
作者： 负雪明烛
id： fuxuemingzhu
个人博客： http://fuxuemingzhu.me/
题目地址：https://leetcode.com/problems/masking-personal-information/description/
题目描述：
We are given a personal information string S, which may represent either an email address or a phone number.
We would like to mask this personal information according to the following rules:
1. Email address:
We define a name to be a string of length ≥ 2 consisting of only lowercase letters a-z or uppercase letters A-Z.
An email address starts with a name, followed by the symbol ‘@’, followed by a name, followed by the dot ‘.’ and followed by a name.
All email addresses are guaranteed to be valid and in the format of “name1@name2.name3”.
To mask an email, all names must be converted to lowercase and all letters between the first and last letter of the first name must be replaced by 5 asterisks '*'.
2. Phone number:
A phone number is a string consisting of only the digits 0-9 or the characters from the set {‘+’, ‘-‘, ‘(‘, ‘)’, ’ ‘}. You may assume a phone number contains 10 to 13 digits.
The last 10 digits make up the local number, while the digits before those make up the country code. Note that the country code is optional. We want to expose only the last 4 digits and mask all other digits.
The local number should be formatted and masked as "***-***-1111", where 1 represents the exposed digits.
To mask a phone number with country code like "+111 111 111 1111", we write it in the form "+***-***-***-1111". The '+' sign and the first '-' sign before the local number should only exist if there is a country code. For example, a 12 digit phone number mask should start with "+**-".
Note that extraneous characters like “(“, “)”, ” “, as well as extra dashes or plus signs not part of the above formatting scheme should be removed.
Return the correct “mask” of the information provided.
Example 1:
Input: "LeetCode@LeetCode.com"
Output: "l*****e@leetcode.com"
Explanation: All names are converted to lowercase, and the letters between the
first and last letter of the first name is replaced by 5 asterisks.
Therefore, "leetcode" -> "l*****e".
Example 2:
Input: "AB@qq.com"
Output: "a*****b@qq.com"
Explanation: There must be 5 asterisks between the first and last letter
of the first name "ab". Therefore, "ab" -> "a*****b".
Example 3:
Input: "1(234)567-890"
Output: "***-***-7890"
Explanation: 10 digits in the phone number, which means all digits make up the local number.
Example 4:
Input: "86-(10)12345678"
Output: "+**-***-***-5678"
Explanation: 12 digits, 2 digits for country code and 10 digits for local number.
Notes:
- S.length <= 40.
- Emails have length at least 8.
- Phone numbers have length at least 10.
题目大意
题目这么长的，应该还是第一次见。
本题的意思是隐藏手机号/邮箱的部分数字。
隐藏邮箱的规则是：全部转成小写，把用户名改成只保留首尾字母，并且两个字母之间用5个*填充
隐藏手机号的规则是：手机号的后10位是本地号码，其余的前面的数字是区号。本地号码直接转成"***-***-末尾四位"格式。区号变成"+区号位数-"。
解题方法
没什么好解释的，看完题就行。
class Solution(object):
def convert_phone(self, phone):
phone = phone.strip().replace(' ', '').replace('(', '').replace(')', '').replace('-', '').replace('+', '')
if len(phone) == 10:
return "***-***-" + phone[-4:]
else:
return "+" + '*' * (len(phone) - 10) + "-***-***-" + phone[-4:]
def convert_email(self, email):
email = email.lower()
first_name, host = email.split('@')
return first_name[0] + '*****' + first_name[-1] + '@' + host
def maskPII(self, S):
"""
:type S: str
:rtype: str
"""
return self.convert_email(S) if '@' in S else self.convert_phone(S)日期
2018 年 6 月 10 日 ———— 等了两天的腾讯比赛复赛B的数据集，结果人家在复赛刚开始就给了。。