复习下数据结构,用栈简单实现逆波兰表达式,参考文档:
http://www.nowamagic.net/librarys/veda/detail/2307
http://www.nowamagic.net/librarys/veda/detail/2306
直接上代码:
/**
*code by lichmama from cnblogs.com
*@逆波兰表达式的C实现
*算术支持的运算模式:
* 四则运算;
* 操作数不得大于9;
* 中间数(即运算当中的临时变量)不得超过127
**/
#include <stdio.h>
#include <stdlib.h> typedef struct __STACK__ {
char op;
struct __STACK__ *next;
}STACK, *PSTACK; void init(PSTACK *);
void push(PSTACK *, char);
void pop(PSTACK *, char *);
void clear(PSTACK *);
void destroy(PSTACK *); char getoplevel(char op){
if(op=='+' || op=='-')
return ;
if(op=='*' || op=='/')
return ;
return ;
} char calc(char *rpn){
char *p=rpn;
char e;
int x, y;
PSTACK pStack;
init(&pStack);
while(*p){
if(<=*p && *p<=){
push(&pStack, *p);
}else {
pop(&pStack, &e);x=e;
pop(&pStack, &e);y=e;
switch(*p){
case '+':push(&pStack, y+x);break;
case '-':push(&pStack, y-x);break;
case '*':push(&pStack, y*x);break;
case '/':push(&pStack, y/x);break;
}
}
p++;
}
pop(&pStack, &e);
free(pStack);pStack=NULL;
return e;
} int main(void){
char e;
char old_exp[]="(3-1)*3+8/2+(9*3/(2+1)+3*4/6)-2=";
char rpn_exp[]="";
char *p=old_exp;
char *r=rpn_exp;
PSTACK gStack;
init(&gStack);
//
while(*p!='\0' && *p!='='){
if(''<=*p && *p<=''){
*r++=(*p-'');
}else if(*p=='('){
push(&gStack, '(');
}else if(*p==')'){
for(;;){
pop(&gStack, &e);
if(e=='(')break;
*r++=e;
}
}else if(*p=='+' || *p=='-' || *p=='*' || *p=='/'){
if(getoplevel(gStack->op)<getoplevel(*p)){
push(&gStack, *p);
}else{ for(;;){
pop(&gStack, &e);
if(getoplevel(e)<getoplevel(*p)){
if(e!='#')push(&gStack, e);
push(&gStack, *p);break;
}
*r++=e;
}
}
}
p++;
}
for(;;){
pop(&gStack, &e);
if(e=='#')break;
*r++=e;
}
//printf("%s\n", rpn_exp);
printf("%d\n", calc(rpn_exp));
//
clear(&gStack);
destroy(&gStack);
return ;
} void init(PSTACK *s){
*s=(PSTACK)malloc(sizeof(STACK));
(*s)->op='#';
(*s)->next=NULL;
} void push(PSTACK *s, char e){
PSTACK p=(PSTACK)malloc(sizeof(STACK));
p->op=e;
p->next=*s;
*s=p;
} void pop(PSTACK *s, char *e){
if((*s)->next){
PSTACK p=(*s);
*e=(*s)->op;
*s=(*s)->next;
free(p);
p=NULL;
}else *e='#';
} void clear(PSTACK *s){
PSTACK p;
while((*s)->next){
p=*s;
*s=(*s)->next;
free(p);
p=NULL;
}
} void destroy(PSTACK *s){
free(*s);
*s=NULL;
}
注:改善操作数的限制可使用整形(或浮点型)数组存放中间变量。