1.在高德地图上绘制的多边形；经纬度逗号分隔格式；上面是用来方便存坐标的对象；下面是方法测试；直接复制代码即可运行
public class Point {
private Double x;
private Double y;
public Point (Double x , Double y) {
this.x = x;
this.y = y;
}
public Double getX() {
return x;
}
public void setX(Double x) {
this.x = x;
}
public Double getY() {
return y;
}
public void setY(Double y) {
this.y = y;
}
}
public class Test01 {
public static void main(String[] args) {
//114.331951,30.64091#114.341049,30.610185#114.331436,30.588058#114.312038,30.56393#114.293498,30.558609#114.267922,30.563784#114.231185,30.57945#114.212303,30.601616#114.235649,30.626878#114.280624,30.646818#
Map [] map=new Map[]{};
Point[] ps = new Point[] { new Point(114.309914,30.599556),//114.309914,30.599556
new Point(114.295688,30.592879),//114.295688,30.592879
new Point(114.292812,30.587726), //114.292812,30.587726
new Point(114.292812,30.587726), //114.292812,30.587726
new Point(114.30058,30.580318),//114.30058,30.580318
new Point(114.303606,30.586959),//114.303606,30.586959
new Point(114.304534,30.594751),//114.304534,30.594751
new Point(114.30838,30.590131),//114.30838,30.590131
new Point(114.308651,30.584182),//114.308651,30.584182
new Point(114.304495,30.584015),//114.304495,30.584015
new Point(114.301301,30.578759),//114.301301,30.578759
new Point(114.309437,30.578528),//114.309437,30.578528
new Point(114.323282,30.592786)};//114.323282,30.592786
Point n1 = new Point(114.303217,30.583553);
Point n2 = new Point(114.307336,30.597592);
Point n3 = new Point(114.286565,30.590056);
Point y1 = new Point(114.227342,30.587987);
Point y2 = new Point(120.1866 , 30.2672);
Point y4 = new Point(120.1869 , 30.2718);
System.out.println( "n1:" + isPtInPoly(n1.getX() , n1.getY() , ps));
System.out.println( "n2:" + isPtInPoly(n2.getX() , n2.getY() , ps));
System.out.println( "n3:" + isPtInPoly(n3.getX() , n3.getY() , ps));
System.out.println( "y1:" + isPtInPoly(y1.getX() , y1.getY() , ps));
System.out.println( "y2:" + isPtInPoly(y2.getX() , y2.getY() , ps));
System.out.println( "y4:" + isPtInPoly(y4.getX() , y4.getY() , ps));
}
public static boolean isPtInPoly (double ALon , double ALat , Point[] ps) {
int iSum, iCount, iIndex;
double dLon1 = 0, dLon2 = 0, dLat1 = 0, dLat2 = 0, dLon;
if (ps.length < 3) {
return false;
}
iSum = 0;
iCount = ps.length;
for (iIndex = 0; iIndex<iCount;iIndex++) {
if (iIndex == iCount - 1) {
dLon1 = ps[iIndex].getX();
dLat1 = ps[iIndex].getY();
dLon2 = ps[0].getX();
dLat2 = ps[0].getY();
} else {
dLon1 = ps[iIndex].getX();
dLat1 = ps[iIndex].getY();
dLon2 = ps[iIndex + 1].getX();
dLat2 = ps[iIndex + 1].getY();
}
// 以下语句判断A点是否在边的两端点的水平平行线之间，在则可能有交点，开始判断交点是否在左射线上
if (((ALat >= dLat1) && (ALat < dLat2)) || ((ALat >= dLat2) && (ALat < dLat1))) {
if (Math.abs(dLat1 - dLat2) > 0) {
//得到 A点向左射线与边的交点的x坐标：
dLon = dLon1 - ((dLon1 - dLon2) * (dLat1 - ALat) ) / (dLat1 - dLat2);
// 如果交点在A点左侧（说明是做射线与 边的交点），则射线与边的全部交点数加一：
if (dLon < ALon) {
iSum++;
}
}
}
}
if ((iSum % 2) != 0) {
return true;
}
return false;
}
}