将一个多层嵌套的序列展开成一个单层列表
可以写一个包含yield from 语句的递归生成器来轻松解决这个问题。
from collections import Iterable
def flatten(items, ignore_types=(str, bytes)):
for x in items:
if isinstance(x, Iterable) and not isinstance(x, ignore_types):
yield from flatten(x)
else:
yield x
items = [1, 2, [3, 4, [5, 6], 7], 8]
# Produces 1 2 3 4 5 6 7 8
for x in flatten(items):
print(x) bb=list(flatten(items))
print(bb)