Appium+python 一个简单的登录测试实例

# coding=utf-8

from appium import webdriver
import time
import unittest
import os
import HTMLTestRunner class LoginTestLizi(unittest.TestCase):
def setUp(self):
desired_caps = {}
desired_caps['platformName'] = 'Android' # 设备系统
desired_caps['platformVersion'] = '6.0.1' # 设备系统版本
desired_caps['deviceName'] = '270f2988' # 设备名称
desired_caps['appPackage'] = 'com.lizi.app' # 测试app包名
desired_caps['appActivity'] = '.activity.MainActivity' # 测试appActivity
self.driver = webdriver.Remote('http://localhost:4723/wd/hub', desired_caps) # 启动app def test_login(self):
driver = self.driver
# 进入首页后点击‘我的’按钮
driver.find_element_by_name(u'我的').click()
time.sleep(2)
# 点击登录头像按钮,进行登录,跳转到登录界面
driver.find_element_by_id('com.lizi.app:id/user_login_iv').click()
time.sleep(2)
# 输入用户名
driver.find_element_by_id('com.lizi.app:id/zhanghao_edittext').send_keys('')
# 输入密码
driver.find_element_by_id('com.lizi.app:id/password_edittext').send_keys('password')
# 点击确认登录按钮
driver.find_element_by_id('com.lizi.app:id/login_button').click() time.sleep(3)
# 登录成功,页面下滑,不然点击不到设置按钮
driver.swipe(500, 200, 500, 800, 0)
time.sleep(2)
# 获取登录后的昵称
name = driver.find_element_by_id('com.lizi.app:id/login_username_tv').text # 添加断言,若昵称不正确,则打印错误信息
try:
assert 'No_matter' in name
print 'loginUser is right'
except AssertionError as e:
print 'loginUser is Error' # 点击设置按钮,进入设置页面
driver.find_element_by_id('com.lizi.app:id/setting_imageView').click()
# 点击退出按钮
driver.find_element_by_id('com.lizi.app:id/exit_button').click() def tearDown(self):
self.driver.quit() if __name__ == '__main__':
suite = unittest.TestSuite()
suite.addTest(LoginTestLizi('test_login'))
filename = 'C:\\Temp\\app.html'
fb = file(filename, 'wb')
runner = HTMLTestRunner.HTMLTestRunner(stream=fb, title='liziapptestreport', description='liziapp')
runner.run(suite)
fb.close()
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