Python 根据地址获取经纬度及求距离

方法一:

使用Geopy包 : https://github.com/geopy/geopy   (仅能精确到城镇,具体街道无结果返回)

from geopy.geocoders import Nominatim

#使用geopy查询
def geocodeN(address):
gps=Nominatim()
location=gps.geocode(address)
return location.longitude,location.latitude

方法二:

使用高德地图或百度地图API,key可去官网申请替换

import requests

#使用高德API
def geocodeG(address):
par = {'address': address, 'key': 'cb649a25c1f81c1451adbeca73623251'}
base = 'http://restapi.amap.com/v3/geocode/geo'
response = requests.get(base, par)
answer = response.json()
GPS=answer['geocodes'][0]['location'].split(",")
return GPS[0],GPS[1] #使用百度API
def geocodeB(address):
base = url = "http://api.map.baidu.com/geocoder?address=" + address + "&output=json&key=f247cdb592eb43ebac6ccd27f796e2d2"
response = requests.get(base)
answer = response.json()
return answer['result']['location']['lng'],answer['result']['location']['lat']

计算两个经纬度间距离:

from math import radians, cos, sin, asin, sqrt

#计算两点间距离-m
def geodistance(lng1,lat1,lng2,lat2):
lng1, lat1, lng2, lat2 = map(radians, [lng1, lat1, lng2, lat2])
dlon=lng2-lng1
dlat=lat2-lat1
a=sin(dlat/2)**2 + cos(lat1) * cos(lat2) * sin(dlon/2)**2
dis=2*asin(sqrt(a))*6371*1000
return dis
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