我想在Tkinter中实现一个满足以下要求的进度条：

>进度栏是主窗口中的唯一元素
>可以通过启动命令来启动,而无需按下任何按钮
>可以等待,直到持续时间未知的任务完成
>只要任务未完成,进度条的指示灯就会不断移动
>可以通过停止命令将其关闭,而无需按下任何停止杆

到目前为止,我有以下代码：

import Tkinter
import ttk
import time

def task(root):
    root.mainloop()

root = Tkinter.Tk()
ft = ttk.Frame()
ft.pack(expand=True, fill=Tkinter.BOTH, side=Tkinter.TOP)
pb_hD = ttk.Progressbar(ft, orient='horizontal', mode='indeterminate')
pb_hD.pack(expand=True, fill=Tkinter.BOTH, side=Tkinter.TOP)
pb_hD.start(50)
root.after(0,task(root))
time.sleep(5) # to be replaced by process of unknown duration
root.destroy()

在这里,问题在于进度条在5秒结束后不会停止.

有人可以帮我发现错误吗？

解决方法:

一旦激活了mainloop,脚本将不会移动到下一行,直到根被销毁为止.
可能还有其他方法可以执行此操作,但我更喜欢使用线程来执行此操作.

像这样

import Tkinter
import ttk
import time
import threading

#Define your Progress Bar function, 
def task(root):
    ft = ttk.Frame()
    ft.pack(expand=True, fill=Tkinter.BOTH, side=Tkinter.TOP)
    pb_hD = ttk.Progressbar(ft, orient='horizontal', mode='indeterminate')
    pb_hD.pack(expand=True, fill=Tkinter.BOTH, side=Tkinter.TOP)
    pb_hD.start(50)
    root.mainloop()

# Define the process of unknown duration with root as one of the input And once done, add root.quit() at the end.
def process_of_unknown_duration(root):
    time.sleep(5)
    print 'Done'
    root.destroy()

# Now define our Main Functions, which will first define root, then call for call for "task(root)" --- that's your progressbar, and then call for thread1 simultaneously which will  execute your process_of_unknown_duration and at the end destroy/quit the root.

def Main():
    root = Tkinter.Tk()
    t1=threading.Thread(target=process_of_unknown_duration, args=(root,))
    t1.start()
    task(root)  # This will block while the mainloop runs
    t1.join()

#Now just run the functions by calling our Main() function,
if __name__ == '__main__':
    Main()

让我知道是否有帮助.