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第一个多重背包题目 真的不理解二进制优化
/http://acm.hdu.edu.cn/webcontest/contest_showproblem.php?cid=10594&pid=1001&ojid

以下是用二进制优化的 不会超时

include

include

include

include

using namespace std;
int dp[200000],a[7];
void zeroOne(int weiht,int value,int c)
{
for(int j=c;j>=weiht;j--)
dp[j]=max(dp[j],dp[j-weiht]+value);
}
void complelet(int weight,int value,int c)
{
for(int j=weight;j<=c;j++)
dp[j]=max(dp[j],dp[j-weight]+value);
}
void duoChong(int weight,int value,int count,int c)
{
if(countvalue>=c)complelet(weight ,value,c);
else
{
int k=1;
while(k<count)
{
zeroOne(kweight,kvalue,c);
count-=k;
k+=k;
}
zeroOne(countweight,countvalue,c);
}
}
int main()
{
int count=0;
while(1)
{
int sum=0;
for(int i=1; i<=6; i++)
{
scanf("%d",&a[i]);
sum+=a[i]i;

    }
    if(sum==0)break;
    printf("Collection #%d:\n",++count);
    if(sum%2==1)
    {
        printf("Can't be divided.\n\n");
        continue;
    }
    int c=sum/2;
    memset(dp,0,sizeof(dp));
    for(int i=1; i<=6; i++)
         duoChong(i,i,a[i],c);
    if(dp[c]==sum/2)printf("Can be divided.\n\n");
    else printf("Can't be divided.\n\n");
}
return 0;

}

直接化为01背包计算 超时

include

include

include

include

using namespace std;
int dp[200000],a[7],w[7];
int main()
{
int count=0;
while(1)
{
int sum=0;
for(int i=1; i<=6; i++)
{
scanf("%d",&a[i]);
sum+=a[i]*i;
w[i]=i;
}
if(sum==0)break;
printf("Collection #%d:\n",++count);
if(sum%2==1)
{
printf("Can't be divided.\n\n");
continue;
}
int c=sum/2;
memset(dp,0,sizeof(dp));
for(int i=1; i<=6; i++)
for(int k=1; k<=a[i]; k++)//有限个数量（超时）
for(int j=c; j>=w[i]; j--)
dp[j]=max(dp[j],dp[j-w[i]]+w[i]);
printf("sum/2=%d\n",dp[sum/2]);
if(dp[c]==sum/2)printf("Can be divided.\n\n");
else printf("Can't be divided.\n\n");
}
return 0;
}

下面是搜索做的 比多重背包快了很多

include

include

include

include

using namespace std;
int op=0;
int mid;
int a[8];
void dfs(int cnt,int sum)
{
if(op)return;
if(sum==mid)
{
op=1;
return ;
}
for(int i=cnt; i>=1; i--)
{
if(a[i])
if(sum+i<=mid)
{
a[i]--;
dfs(i,sum+i);
}
}
}
int main()
{
int count=0;
while(1)
{
int sum=0;
for(int i=1; i<=6; i++)
{
scanf("%d",&a[i]);
sum+=i*a[i];
}
if(sum==0)break;
printf("Collection #%d:\n",++count);
if(sum%2==1)
{
printf("Can't be divided.\n\n");
continue;
}
mid=sum/2;
op=0;
dfs(6,0);
if(op)printf("Can be divided.\n\n");
else printf("Can't be divided.\n\n");

}
return 0;

}