学习课程来源：http://www.bjpowernode.com/javavideo/111.html
1、关于查询结果集的去重？
select distinct job from emp; // distinct关键字去除重复记录。
+-----------+
| job |
+-----------+
| CLERK |
| SALESMAN |
| MANAGER |
| ANALYST |
| PRESIDENT |
+-----------+
select ename,distinct job from emp; //错误
注：distinct只能出现在所有字段的最前面。
select distinct deptno,job from emp;
+--------+-----------+
| deptno | job |
+--------+-----------+
| 20 | CLERK |
| 30 | SALESMAN |
| 20 | MANAGER |
| 30 | MANAGER |
| 10 | MANAGER |
| 20 | ANALYST |
| 10 | PRESIDENT |
| 30 | CLERK |
| 10 | CLERK |
+--------+-----------+
统计岗位的数量？
select count(distinct job) from emp;
+---------------------+
| count(distinct job) |
+---------------------+
| 5 |
+---------------------+
2、连接查询
2.1、什么是连接查询？
在实际开发中，大部分的情况下都不是从单表中查询数据，一般都是多张表联合查询取出最终的结果。
在实际开发中，一般一个业务都会对应多张表，比如：学生和班级，起码两张表。
stuno stuname classno classname
-----------------------------------------------------------------------------------
1 zs 1 北京大兴区亦庄经济技术开发区第二中学高三1班
2 ls 1 北京大兴区亦庄经济技术开发区第二中学高三1班
...
学生和班级信息存储到一张表中，结果就像上面一样，数据会存在大量的重复，导致数据的冗余。
2.2、连接查询的分类
根据语法出现的年代来划分的话，包括：
SQL92（一些老的DBA可能还在使用这种语法。DBA：DataBase Administrator，数据库管理员）
SQL99（比较新的语法）
根据表的连接方式来划分，包括：
内连接：
等值连接
非等值连接
自连接
外连接：
左外连接（左连接）
右外连接（右连接）
全连接（这个很少用）
2.3、笛卡尔积现象
在表的连接查询方面有一种现象被称为：笛卡尔积现象。（笛卡尔乘积现象）
找出每一个员工的部门名称，要求显示员工名和部门名。
EMP表
+--------+--------+
| ename | deptno |
+--------+--------+
| SMITH | 20 |
| ALLEN | 30 |
| WARD | 30 |
| JONES | 20 |
| MARTIN | 30 |
| BLAKE | 30 |
| CLARK | 10 |
| SCOTT | 20 |
| KING | 10 |
| TURNER | 30 |
| ADAMS | 20 |
| JAMES | 30 |
| FORD | 20 |
| MILLER | 10 |
+--------+--------+
DEPT表
+--------+------------+----------+
| DEPTNO | DNAME | LOC |
+--------+------------+----------+
| 10 | ACCOUNTING | NEW YORK |
| 20 | RESEARCH | DALLAS |
| 30 | SALES | CHICAGO |
| 40 | OPERATIONS | BOSTON |
+--------+------------+----------+
select ename,dname from emp,dept;
+--------+------------+
| ename | dname |
+--------+------------+
| SMITH | ACCOUNTING |
| SMITH | RESEARCH |
| SMITH | SALES |
| SMITH | OPERATIONS |
| ALLEN | ACCOUNTING |
| ALLEN | RESEARCH |
| ALLEN | SALES |
| ALLEN | OPERATIONS |
............
56 rows in set (0.00 sec)
笛卡尔积现象：当两张表进行连接查询的时候，没有任何条件进行限制，最终的查询结果条数是两张表记录条数的乘积。
关于表的别名：
select e.ename,d.dname from emp e,dept d;
表的别名有什么好处？
第一：执行效率高。
第二：可读性好。
2.4、怎么避免笛卡尔积现象？
当然是加条件进行过滤。
避免了笛卡尔积现象，也不会会减少记录的匹配次数。次数还是56次，只不过显示的是有效记录。
找出每一个员工的部门名称，要求显示员工名和部门名。
select
e.ename,d.dname
from
emp e , dept d
where
e.deptno = d.deptno; //SQL92，以后不用。
+--------+------------+
| ename | dname |
+--------+------------+
| CLARK | ACCOUNTING |
| KING | ACCOUNTING |
| MILLER | ACCOUNTING |
| SMITH | RESEARCH |
| JONES | RESEARCH |
| SCOTT | RESEARCH |
| ADAMS | RESEARCH |
| FORD | RESEARCH |
| ALLEN | SALES |
| WARD | SALES |
| MARTIN | SALES |
| BLAKE | SALES |
| TURNER | SALES |
| JAMES | SALES |
+--------+------------+
2.5、内连接之等值连接
最大特点是：条件是等量关系。
案例：查询每个员工的部门名称，要求显示员工名和部门名。
SQL92:（太老，不用了）
select
e.ename,d.dname
from
emp e, dept d
where
e.deptno = d.deptno;
SQL99：（常用的）
select
e.ename,d.dname
from
emp e
join
dept d
on
e.deptno = d.deptno;
// inner可以省略的，带着inner目的是可读性好一些。
select
e.ename,d.dname
from
emp e
inner join
dept d
on
e.deptno = d.deptno;
+--------+------------+
| ename | dname |
+--------+------------+
| CLARK | ACCOUNTING |
| KING | ACCOUNTING |
| MILLER | ACCOUNTING |
| SMITH | RESEARCH |
| JONES | RESEARCH |
| SCOTT | RESEARCH |
| ADAMS | RESEARCH |
| FORD | RESEARCH |
| ALLEN | SALES |
| WARD | SALES |
| MARTIN | SALES |
| BLAKE | SALES |
| TURNER | SALES |
| JAMES | SALES |
+--------+------------+
语法：
...
A
join
B
on
连接条件
where
...
SQL99语法结构更清晰一些：表的连接条件和后来的where条件分离了。
2.6、内连接之非等值连接
最大的特点是：连接条件中的关系是非等量关系。
找出每个员工的工资等级，要求显示员工名、工资、工资等级。
select ename,sal from emp; e
+--------+---------+
| ename | sal |
+--------+---------+
| SMITH | 800.00 |
| ALLEN | 1600.00 |
| WARD | 1250.00 |
| JONES | 2975.00 |
| MARTIN | 1250.00 |
| BLAKE | 2850.00 |
| CLARK | 2450.00 |
| SCOTT | 3000.00 |
| KING | 5000.00 |
| TURNER | 1500.00 |
| ADAMS | 1100.00 |
| JAMES | 950.00 |
| FORD | 3000.00 |
| MILLER | 1300.00 |
+--------+---------+
select * from salgrade; s
+-------+-------+-------+
| GRADE | LOSAL | HISAL |
+-------+-------+-------+
| 1 | 700 | 1200 |
| 2 | 1201 | 1400 |
| 3 | 1401 | 2000 |
| 4 | 2001 | 3000 |
| 5 | 3001 | 9999 |
+-------+-------+-------+
select
e.ename,e.sal,s.grade
from
emp e
join
salgrade s
on
e.sal between s.losal and s.hisal;
// inner可以省略
select
e.ename,e.sal,s.grade
from
emp e
inner join
salgrade s
on
e.sal between s.losal and s.hisal;
+--------+---------+-------+
| ename | sal | grade |
+--------+---------+-------+
| SMITH | 800.00 | 1 |
| ALLEN | 1600.00 | 3 |
| WARD | 1250.00 | 2 |
| JONES | 2975.00 | 4 |
| MARTIN | 1250.00 | 2 |
| BLAKE | 2850.00 | 4 |
| CLARK | 2450.00 | 4 |
| SCOTT | 3000.00 | 4 |
| KING | 5000.00 | 5 |
| TURNER | 1500.00 | 3 |
| ADAMS | 1100.00 | 1 |
| JAMES | 950.00 | 1 |
| FORD | 3000.00 | 4 |
| MILLER | 1300.00 | 2 |
+--------+---------+-------+
2.7、自连接：最大的特点是：一张表看做两张表。自己连接自己。
找出每个员工的上级领导，要求显示员工名和对应的领导名。
select empno,ename,mgr from emp;
emp a 员工表
+-------+--------+------+
| empno | ename | mgr |
+-------+--------+------+
| 7369 | SMITH | 7902 |
| 7499 | ALLEN | 7698 |
| 7521 | WARD | 7698 |
| 7566 | JONES | 7839 |
| 7654 | MARTIN | 7698 |
| 7698 | BLAKE | 7839 |
| 7782 | CLARK | 7839 |
| 7788 | SCOTT | 7566 |
| 7839 | KING | NULL |
| 7844 | TURNER | 7698 |
| 7876 | ADAMS | 7788 |
| 7900 | JAMES | 7698 |
| 7902 | FORD | 7566 |
| 7934 | MILLER | 7782 |
+-------+--------+------+
emp b 领导表
+-------+--------+
| empno | ename |
+-------+--------+
| 7566 | JONES |
| 7698 | BLAKE |
| 7782 | CLARK |
| 7788 | SCOTT |
| 7839 | KING |
| 7902 | FORD |
+-------+--------+
员工的领导编号 = 领导的员工编号
select
a.ename as '员工名',b.ename as '领导名'
from
emp a
inner join
emp b
on
a.mgr = b.empno;
+--------+--------+
| 员工名 | 领导名 |
+--------+--------+
| SMITH | FORD |
| ALLEN | BLAKE |
| WARD | BLAKE |
| JONES | KING |
| MARTIN | BLAKE |
| BLAKE | KING |
| CLARK | KING |
| SCOTT | JONES |
| TURNER | BLAKE |
| ADAMS | SCOTT |
| JAMES | BLAKE |
| FORD | JONES |
| MILLER | CLARK |
+--------+--------+
2.8、外连接
什么是外连接，和内连接有什么区别？
内连接：
假设A和B表进行连接，使用内连接的话，凡是A表和B表能够匹配上的记录查询出来，这就是内连接。
AB两张表没有主副之分，两张表是平等的。
外连接：
假设A和B表进行连接，使用外连接的话，AB两张表中有一张表是主表，一张表是副表，主要查询主表中
的数据，捎带着查询副表，当副表中的数据没有和主表中的数据匹配上，副表自动模拟出NULL与之匹配。
外连接的分类？
左外连接（左连接）：表示左边的这张表是主表。
右外连接（右连接）：表示右边的这张表是主表。
左连接有右连接的写法，右连接也会有对应的左连接的写法。
找出每个员工的上级领导？（所有员工必须全部查询出来。）
emp a 员工表
+-------+--------+------+
| empno | ename | mgr |
+-------+--------+------+
| 7369 | SMITH | 7902 |
| 7499 | ALLEN | 7698 |
| 7521 | WARD | 7698 |
| 7566 | JONES | 7839 |
| 7654 | MARTIN | 7698 |
| 7698 | BLAKE | 7839 |
| 7782 | CLARK | 7839 |
| 7788 | SCOTT | 7566 |
| 7839 | KING | NULL |
| 7844 | TURNER | 7698 |
| 7876 | ADAMS | 7788 |
| 7900 | JAMES | 7698 |
| 7902 | FORD | 7566 |
| 7934 | MILLER | 7782 |
+-------+--------+------+
emp b 领导表
+-------+--------+
| empno | ename |
+-------+--------+
| 7566 | JONES |
| 7698 | BLAKE |
| 7782 | CLARK |
| 7788 | SCOTT |
| 7839 | KING |
| 7902 | FORD |
+-------+--------+
内连接：
select
a.ename '员工', b.ename '领导'
from
emp a
join
emp b
on
a.mgr = b.empno;
外连接：（左外连接/左连接）
select
a.ename '员工', b.ename '领导'
from
emp a
left join
emp b
on
a.mgr = b.empno;
// outer是可以省略的。
select
a.ename '员工', b.ename '领导'
from
emp a
left outer join
emp b
on
a.mgr = b.empno;
外连接：（右外连接/右连接）
select
a.ename '员工', b.ename '领导'
from
emp b
right join
emp a
on
a.mgr = b.empno;
// outer可以省略。
select
a.ename '员工', b.ename '领导'
from
emp b
right outer join
emp a
on
a.mgr = b.empno;
+--------+-------+
| 员工 | 领导 |
+--------+-------+
| SMITH | FORD |
| ALLEN | BLAKE |
| WARD | BLAKE |
| JONES | KING |
| MARTIN | BLAKE |
| BLAKE | KING |
| CLARK | KING |
| SCOTT | JONES |
| KING | NULL |
| TURNER | BLAKE |
| ADAMS | SCOTT |
| JAMES | BLAKE |
| FORD | JONES |
| MILLER | CLARK |
+--------+-------+
外连接最重要的特点是：主表的数据无条件的全部查询出来。
找出哪个部门没有员工？
EMP表
+-------+--------+-----------+------+------------+---------+---------+--------+
| EMPNO | ENAME | JOB | MGR | HIREDATE | SAL | COMM | DEPTNO |
+-------+--------+-----------+------+------------+---------+---------+--------+
| 7369 | SMITH | CLERK | 7902 | 1980-12-17 | 800.00 | NULL | 20 |
| 7499 | ALLEN | SALESMAN | 7698 | 1981-02-20 | 1600.00 | 300.00 | 30 |
| 7521 | WARD | SALESMAN | 7698 | 1981-02-22 | 1250.00 | 500.00 | 30 |
| 7566 | JONES | MANAGER | 7839 | 1981-04-02 | 2975.00 | NULL | 20 |
| 7654 | MARTIN | SALESMAN | 7698 | 1981-09-28 | 1250.00 | 1400.00 | 30 |
| 7698 | BLAKE | MANAGER | 7839 | 1981-05-01 | 2850.00 | NULL | 30 |
| 7782 | CLARK | MANAGER | 7839 | 1981-06-09 | 2450.00 | NULL | 10 |
| 7788 | SCOTT | ANALYST | 7566 | 1987-04-19 | 3000.00 | NULL | 20 |
| 7839 | KING | PRESIDENT | NULL | 1981-11-17 | 5000.00 | NULL | 10 |
| 7844 | TURNER | SALESMAN | 7698 | 1981-09-08 | 1500.00 | 0.00 | 30 |
| 7876 | ADAMS | CLERK | 7788 | 1987-05-23 | 1100.00 | NULL | 20 |
| 7900 | JAMES | CLERK | 7698 | 1981-12-03 | 950.00 | NULL | 30 |
| 7902 | FORD | ANALYST | 7566 | 1981-12-03 | 3000.00 | NULL | 20 |
| 7934 | MILLER | CLERK | 7782 | 1982-01-23 | 1300.00 | NULL | 10 |
+-------+--------+-----------+------+------------+---------+---------+--------+
DEPT
+--------+------------+----------+
| DEPTNO | DNAME | LOC |
+--------+------------+----------+
| 10 | ACCOUNTING | NEW YORK |
| 20 | RESEARCH | DALLAS |
| 30 | SALES | CHICAGO |
| 40 | OPERATIONS | BOSTON |
+--------+------------+----------+
select
d.*
from
emp e
right join
dept d
on
e.deptno = d.deptno
where
e.empno is null;
+--------+------------+--------+
| DEPTNO | DNAME | LOC |
+--------+------------+--------+
| 40 | OPERATIONS | BOSTON |
+--------+------------+--------+
2.9、三张表怎么连接查询？
找出每一个员工的部门名称以及工资等级。
EMP e
+-------+--------+---------+--------+
| empno | ename | sal | deptno |
+-------+--------+---------+--------+
| 7369 | SMITH | 800.00 | 20 |
| 7499 | ALLEN | 1600.00 | 30 |
| 7521 | WARD | 1250.00 | 30 |
| 7566 | JONES | 2975.00 | 20 |
| 7654 | MARTIN | 1250.00 | 30 |
| 7698 | BLAKE | 2850.00 | 30 |
| 7782 | CLARK | 2450.00 | 10 |
| 7788 | SCOTT | 3000.00 | 20 |
| 7839 | KING | 5000.00 | 10 |
| 7844 | TURNER | 1500.00 | 30 |
| 7876 | ADAMS | 1100.00 | 20 |
| 7900 | JAMES | 950.00 | 30 |
| 7902 | FORD | 3000.00 | 20 |
| 7934 | MILLER | 1300.00 | 10 |
+-------+--------+---------+--------+
DEPT d
+--------+------------+----------+
| DEPTNO | DNAME | LOC |
+--------+------------+----------+
| 10 | ACCOUNTING | NEW YORK |
| 20 | RESEARCH | DALLAS |
| 30 | SALES | CHICAGO |
| 40 | OPERATIONS | BOSTON |
+--------+------------+----------+
SALGRADE s
+-------+-------+-------+
| GRADE | LOSAL | HISAL |
+-------+-------+-------+
| 1 | 700 | 1200 |
| 2 | 1201 | 1400 |
| 3 | 1401 | 2000 |
| 4 | 2001 | 3000 |
| 5 | 3001 | 9999 |
+-------+-------+-------+
注意，解释一下：
....
A
join
B
join
C
on
...
表示：A表和B表先进行表连接，连接之后A表继续和C表进行连接。
select
e.ename,d.dname,s.grade
from
emp e
join
dept d
on
e.deptno = d.deptno
join
salgrade s
on
e.sal between s.losal and s.hisal;
+--------+------------+-------+
| ename | dname | grade |
+--------+------------+-------+
| SMITH | RESEARCH | 1 |
| ALLEN | SALES | 3 |
| WARD | SALES | 2 |
| JONES | RESEARCH | 4 |
| MARTIN | SALES | 2 |
| BLAKE | SALES | 4 |
| CLARK | ACCOUNTING | 4 |
| SCOTT | RESEARCH | 4 |
| KING | ACCOUNTING | 5 |
| TURNER | SALES | 3 |
| ADAMS | RESEARCH | 1 |
| JAMES | SALES | 1 |
| FORD | RESEARCH | 4 |
| MILLER | ACCOUNTING | 2 |
+--------+------------+-------+
找出每一个员工的部门名称、工资等级、以及上级领导。
select
e.ename '员工',d.dname,s.grade,e1.ename '领导'
from
emp e
join
dept d
on
e.deptno = d.deptno
join
salgrade s
on
e.sal between s.losal and s.hisal
left join
emp e1
on
e.mgr = e1.empno;
+--------+------------+-------+-------+
| 员工 | dname | grade | 领导 |
+--------+------------+-------+-------+
| SMITH | RESEARCH | 1 | FORD |
| ALLEN | SALES | 3 | BLAKE |
| WARD | SALES | 2 | BLAKE |
| JONES | RESEARCH | 4 | KING |
| MARTIN | SALES | 2 | BLAKE |
| BLAKE | SALES | 4 | KING |
| CLARK | ACCOUNTING | 4 | KING |
| SCOTT | RESEARCH | 4 | JONES |
| KING | ACCOUNTING | 5 | NULL |
| TURNER | SALES | 3 | BLAKE |
| ADAMS | RESEARCH | 1 | SCOTT |
| JAMES | SALES | 1 | BLAKE |
| FORD | RESEARCH | 4 | JONES |
| MILLER | ACCOUNTING | 2 | CLARK |
+--------+------------+-------+-------+