-//发现自己写的清除aud脚本通用性不好,每次都要修改,写一个通用脚本.而且一些服务器有多个实例的情况.
--//编写脚本如下:

cat /usr/local/bin/purge_oracle_aud.sh

! /bin/bash

purge oracle audit log

odebug=${ODEBUG:-0}

if (( $# < 1 ))
then

    echo "arguments is insufficiency , argumentN = oracle_sid N>=1"
    exit  1

fi

for i in "$@"
do

    if [ -d /u01/app/oracle/admin/${i}/adump/ ]
    then
            echo
            echo "start purge oracle audit ${i} at : " $(/bin/date +‘%Y/%m/%d %T‘)
            /usr/bin/find /u01/app/oracle/admin/${i}/adump/ -mtime +30  -name "${i}_ora_*.aud" -print -delete
            echo "end   purge oracle auditwww.cungun.com ${i} at : " $(/bin/date +‘%Y/%m/%d %T‘)
            echo
    else
            echo "/u01/app/oracle/admin/${i}/adump/ directory is not exist"
            exit 2
    fi

done

chmod 700 /usr/local/bin/purge_oracle_aud.sh

--//还是通用性不好,没有利用环境变量$ORACLE_BASE,先暂时这样没时间.

2.加入crontab页游脚本:

cat /etc/cron.d/ntp

34 6 * root /usr/local/bin/purge_oracle_aud.sh dbcndg2 >> /var/log/purge_oracle_aud.log 2>&1
--//每天6:34分执行.

3.修改/etc/logrotate.d/oracle,加入如下:

grep -v "^#" /etc/logrotate.d/oracle

/var/log/purge_oracle_aud.log
{

size=20M
rotate 5
copytruncate
compress
notifempty
missingok

}

--//audit更加合理一些.

如何能够清除aud脚本？