<?php

echo $_GET['key'];

?>

当url为http://test.com/c.php?key=999时，正常输出：999

当url为http://test.com/c.php?key=9#888时，仅仅能输出：9

而我想要获得的是9#888，那要怎么办呢？仅仅能在把9#888传递给key的这个环节想办法。

<input placeholder="输入SN码" type="text" id="searchs" name="searchs" />

<a class='btn' onclick="searchsn();" href="javascript:;">查询</a>

<script>

    function searchsn() {

        var keys = $('#searchs').val();

        if (keys == '') {

            alert('请填写SN码');

            return false;

        }

        keys = escape(keys); //对字符串进行编码，* @ - _ + . / 这几个字符除外

        window.location.href = 'c.php?key=' + keys;

    }

</script>

假设是通过php的header()跳转传递带“#”的參数的话：

a.php

<?php

$query = http_build_query(array('key'=>'66#77'));

// var_dump($query);  //string 'key=66%2377' (length=11)

header("location:http://test.com/b.php?$query");

?>

b.php

<?php

var_dump($_GET['key']);  //string '66#77' (length=5)

?>