Newtonsoft Json.NET是.NET生态下标准json解析库，但是不支持 Unity 引擎。但 GitHub 上有一个可以支持 Unity 的库Newtonsoft Json.NET for Unity3D。本文来介绍一下在 Unity 使用 Newtonsoft 库进行 json 解析。支持序列化字典类型。Unity 自带的 JsonUtility 不支持字典类型。
在https://github.com/SaladLab/Json.Net.Unity3D/releases下载 unitypackage 导入到 Unity 工程里面。
- 对象序列化为 json 字符串
//先定义一个需要序列化的People类
[Serializable]
public class People
{
public string name;
public int age;
public DateTime birthday;
public bool isMarried;
public float money;
}
//序列化 Serialize
public void SerializeJson()
{
People zhangsan = new People();
zhangsan.name = "张三";
zhangsan.age = 20;
zhangsan.birthday = DateTime.Now.AddYears(-20);
zhangsan.isMarried = false;
zhangsan.money = 10.0f;
string jsonStr = JsonConvert.SerializeObject(zhangsan);
Debug.Log("zhangsan json: " + jsonStr);
//output: zhangsan json: {"name":"张三","age":20,"birthday":"1999-03-31T17:15:29.489553+08:00","isMarried":false,"money":10.0}
}
- json 字符串反序列化为对象
//反序列化 Deserialize
public void DeserializeJson()
{
string jsonStr = "{\"name\" :\"张三\",\"age\":30,\"birthday\":\"1990-03-31T17:15:29\",\"isMarried\":true,\"money\":10.0}";
People zhangsan = JsonConvert.DeserializeObject<People>(jsonStr);
Debug.Log("zhangsan.name " + zhangsan.name + " birthday: " + zhangsan.birthday + " isMarried: " + zhangsan.isMarried);
//output: zhangsan.name 张三 birthday: 03/31/1990 17:15:29 isMarried: True
}
- 序列化对象数组
public void SerializeArray()
{
People[] array = new People[4];
for (int i = 0; i < array.Length; i++)
{
People people = new People();
people.name = "People" + i.ToString();
people.age = 18 + i;
people.birthday = DateTime.Now.AddYears(-18-i);
people.isMarried = true;
people.money = 1000 * i;
array[i] = people;
}
string strs = JsonConvert.SerializeObject(array);
Debug.Log("array: " + strs);
//output: array: [{"name":"People0","age":18,"birthday":"2001-03-31T18:02:35.038662+08:00","isMarried":true,"money":0.0},
//{"name":"People1","age":19,"birthday":"2000-03-31T18:02:35.039509+08:00","isMarried":true,"money":1000.0},
//{"name":"People2","age":20,"birthday":"1999-03-31T18:02:35.039512+08:00","isMarried":true,"money":2000.0},
//{"name":"People3","age":21,"birthday":"1998-03-31T18:02:35.039513+08:00","isMarried":true,"money":3000.0}]
}
- 反序列化对象数组
public void DeserializeArray()
{
JArray jArray = JArray.Parse("[{\"name\":\"People0\",\"age\":18,\"birthday\":\"2001-03-31T18:02:35.038662\",\"isMarried\":true,\"money\":0.0},{\"name\":\"People1\",\"age\":19,\"birthday\":\"2000-03-31T18:02:35.039509\",\"isMarried\":true,\"money\":1000.0},{\"name\":\"People2\",\"age\":20,\"birthday\":\"1999-03-31T18:02:35.039512\",\"isMarried\":true,\"money\":2000.0}]");
Debug.Log(jArray.Count);
foreach (var item in jArray)
{
Debug.Log("item path: " + item.Path + " string: " + item.ToString());
}
//outpus:
//3
//item path: [0] string: {
//"name": "People0",
// "age": 18,
// "birthday": "2001-03-31T18:02:35.038662",
// "isMarried": true,
// "money": 0.0
//}
//item path: [1] string: {
// "name": "People1",
// "age": 19,
// "birthday": "2000-03-31T18:02:35.039509",
// "isMarried": true,
// "money": 1000.0
//}
//item path: [2] string: {
// "name": "People2",
// "age": 20,
// "birthday": "1999-03-31T18:02:35.039512",
// "isMarried": true,
// "money": 2000.0
//}
People[] peoples = jArray.ToObject<People[]>();
for (int i = 0; i < peoples.Length; i++)
{
Debug.Log("peoples " + i.ToString() + " " + peoples[i].name + " " + peoples[i].birthday + " " + peoples[i].money);
}
//output:
//peoples 0 People0 03/31/2001 18:02:35 0
//peoples 1 People1 03/31/2000 18:02:35 1000
//peoples 2 People2 03/31/1999 18:02:35 2000
}
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