Codeforces Round #650 (Div. 3)

比赛链接:Here

1367A. Short Substrings

<details open="" class="warn">  Description  

一个字符串 abac,然后把所有长度为2的子串加起来变成新串,abbaac,由 ab ba ac组成。现在给出新串,找出原串。


1367B. Even Array

1367C. Social Distance

1367D. Task On The Board

1367E. Necklace Assembly

1367F1. Flying Sort (Easy Version)

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