Codeforces Round #650 (Div. 3)2024-01-03 10:38:04比赛链接:Here 1367A. Short Substrings <details open="" class="warn"> Description 一个字符串 abac,然后把所有长度为2的子串加起来变成新串,abbaac,由 ab ba ac组成。现在给出新串,找出原串。 1367B. Even Array 1367C. Social Distance 1367D. Task On The Board 1367E. Necklace Assembly 1367F1. Flying Sort (Easy Version) 上一篇:Believing Process 力扣328.奇偶链表下一篇:Uva 11464 偶数矩阵(Even Parity)