#进阶7:连接查询 /* 多表连接:查询的字段来自多个表 按功能分类: 内连接: 等值连接 非等值连接 自连接 外连接: 左外连接 右外连接 全外连接 交叉连接 */ USE girls; SELECT * FROM beauty; SELECT * FROM boys; #SQL92语法 #一、内连接 #1、等值连接 #案例1:查询女生对应的男生名 SELECT name, boyName FROM beauty, boys WHERE beauty.boyfriend_id = boys.id; #案例2:查询员工名和对应的部门名 SELECT last_name, department_name FROM myemployees.employees, myemployees.departments WHERE employees.department_id = departments.department_id; #使用别名 #如果有重名,可以这样解决。但如果表使用了别名,就不能再在查询中用原名 SELECT E.last_name, D.department_name FROM myemployees.employees AS E, myemployees.departments AS D WHERE E.department_id = D.department_id; USE myemployees; #加筛选 #案例3:查询有奖金的员工名、部门名 SELECT last_name, department_name, commission_pct FROM employees as e, departments as d WHERE (e.department_id = d.department_id) AND (e.commission_pct IS NOT NULL); #案例4:查询城市名中第二个字符为o的部门名和城市名 SELECT department_name, city FROM departments as d, locations as l WHERE (d.location_id = l.location_id) AND (department_name LIKE ‘_O%‘); # 加分组 #案例5:查询每个城市的部门个数 SELECT count(*), city FROM departments as d, locations as l WHERE d.location_id = l.location_id GROUP BY city; #加排序 #案例6:查询每个工种的工种名和员工个数,并且按员工个数降序 SELECT job_title, count(*) FROM employees as e, jobs as j WHERE e.job_id = j.job_id GROUP BY job_title ORDER BY count(*) DESC; #多表连接 #案例7:查询员工名、部门名和所在的城市 SELECT last_name, department_name, city FROM employees as e, departments as d, locations as l WHERE e.department_id = d.department_id AND d.location_id = l.location_id; SELECT * FROM job_grades; #2、非等值连接 #案例8:查询员工工资和工资级别 SELECT salary, grade_level FROM employees as e, job_grades as g WHERE salary BETWEEN g.lowest_sal AND g.highest_sal ORDER BY grade_level; #3、自连接 #案例9:查询员工名和领导的名称 SELECT e1.last_name as 员工, e2.last_name as 领导 FROM employees as e1, employees as e2 WHERE e1.manager_id = e2.employee_id; #SQL99语法 /* SELECT 查询列表 FROM 表1 别名 【连接类型】 JOIN 表2 别名 ON 连接条件 【WHERE 筛选条件】 */ #一、内连接:INNER /* SELECT 查询列表 FROM 表1 别名 INNER JOIN 表2 别名 ON 连接条件 【WHERE 筛选条件】 用于查询多个表中都有的记录,两个表的交集 */ #1、等值连接 #案例1:查询员工名、部门名 SELECT last_name, department_name FROM employees as e INNER JOIN departments as d ON e.department_id = d.department_id; #案例2:查询员工名、部门名、工种名,并按部门名降序 SELECT last_name, department_name, job_title FROM employees as e INNER JOIN departments as d ON e.department_id = d.department_id INNER JOIN jobs as j ON e.job_id = j.job_id ORDER BY department_name DESC; #2、非等值连接 #案例3:查询员工工资和工资级别 SELECT salary, grade_level FROM employees as e INNER JOIN job_grades as g ON salary BETWEEN g.lowest_sal AND g.highest_sal ORDER BY grade_level; #案例4:查询每个工资级别>20的个数,并且按工资级别降序 SELECT count(*), grade_level FROM employees as e INNER JOIN job_grades as g ON e.salary BETWEEN g.lowest_sal AND g.highest_sal GROUP BY grade_level HAVING count(*) > 20 ORDER BY grade_level DESC; #3、自连接 #案例5:查询包含k字符的员工名、及其领导的名称 SELECT e1.last_name as 员工, e2.last_name as 领导 FROM employees as e1 INNER JOIN employees as e2 ON e1.manager_id = e2.employee_id WHERE e1.last_name LIKE ‘%k%‘; #二、外连接 /* 用于查询一个表中有、另一个表中没有的记录。主从表的交集+主从表的差集 有主从表之分 1、外连接的查询结果为主表中的所有记录 如果从表中有和它匹配的,则显示匹配的值 如果从表中没有和它匹配的,则显示null 外连接的查询结果=内连接结果+主表有而从表中没有的记录 2、左外连接,left join 左边是主表 右外连接,right join 右边是主表 3、交换顺序,左外、右外等价 */ #1、左外连接:LEFT 【OUTER】 USE girls; #案例1:查询男友不在男生表中的的女生名 SELECT b.name FROM beauty as b LEFT OUTER JOIN boys as bo ON b.boyfriend_id = bo.id WHERE bo.id IS NULL; # id是主键 #2、右外连接:RIGHT 【OUTER】 #交换顺序,主表在后,和左外连接等价 SELECT b.name FROM boys as bo RIGHT OUTER JOIN beauty as b ON b.boyfriend_id = bo.id WHERE bo.id IS NULL; #案例2:查询没有员工的部门 USE myemployees; SELECT d.*, e.employee_id FROM departments as d LEFT OUTER JOIN employees as e ON d.department_id = e.department_id WHERE e.department_id IS NULL; #3、全外连接:FULL 【OUTER】 #查询的是两个表的并集 #三、交叉连接:CROSS #两个表的笛卡尔积 #多表连接案例 #查询编号>3的女生的男友信息,如果有则列出详细,如果没有则用null填充 USE girls; SELECT b.id, b.name, bo.* FROM beauty as b LEFT OUTER JOIN boys as bo ON b.boyfriend_id = bo.id WHERE b.id > 3; #查询哪个城市没有部门 USE myemployees; SELECT l.city FROM locations as l LEFT OUTER JOIN departments as d ON l.location_id = d.location_id WHERE d.location_id IS NULL; #查询部门名为Sal或IT的员工信息 SELECT e.*, d.department_name FROM employees as e INNER JOIN departments as d ON e.department_id = d.department_id WHERE d.department_name IN (‘Sal‘, ‘IT‘);