Running total for Oracle:
SELECT somedate, somevalue,
SUM(somevalue) OVER(ORDER BY somedate
ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW)
AS RunningTotal
FROM Table
from http://www.codeproject.com/Articles/300785/Calculating-simple-running-totals-in-SQL-Server
Introduction
One typical question is, how to calculate running totals in SQL Server. There are several ways of doing it and this article tries to explain a few of them.
Test environment
First we need a table for the data. To keep things simple, let‘s create a table with just an auto incremented id
and a value
field.
--------------------------------------------------------------------
-- table for test
--------------------------------------------------------------------
CREATE TABLE RunTotalTestData (
id int not null identity(1,1) primary key,
value int not null
);
And populate it with some data:
--------------------------------------------------------------------
-- test data
--------------------------------------------------------------------
INSERT INTO RunTotalTestData (value) VALUES (1);
INSERT INTO RunTotalTestData (value) VALUES (2);
INSERT INTO RunTotalTestData (value) VALUES (4);
INSERT INTO RunTotalTestData (value) VALUES (7);
INSERT INTO RunTotalTestData (value) VALUES (9);
INSERT INTO RunTotalTestData (value) VALUES (12);
INSERT INTO RunTotalTestData (value) VALUES (13);
INSERT INTO RunTotalTestData (value) VALUES (16);
INSERT INTO RunTotalTestData (value) VALUES (22);
INSERT INTO RunTotalTestData (value) VALUES (42);
INSERT INTO RunTotalTestData (value) VALUES (57);
INSERT INTO RunTotalTestData (value) VALUES (58);
INSERT INTO RunTotalTestData (value) VALUES (59);
INSERT INTO RunTotalTestData (value) VALUES (60);
The scenario is to fetch a running total when the data is ordered ascending by the id
field.
Correlated scalar query
One very traditional way is to use a correlated scalar query to fetch the running total so far. The query could look like:
--------------------------------------------------------------------
-- correlated scalar
--------------------------------------------------------------------
SELECT a.id, a.value, (SELECT SUM(b.value)
FROM RunTotalTestData b
WHERE b.id <= a.id)
FROM RunTotalTestData a
ORDER BY a.id;
When this is run, the results are:
id value running total
-- ----- -------------
1 1 1
2 2 3
3 4 7
4 7 14
5 9 23
6 12 35
7 13 48
8 16 64
9 22 86
10 42 128
11 57 185
12 58 243
13 59 302
14 60 362
So there it was. Along with the actual row values, we have a running total. The scalar query simply fetches the sum of the value
field from the rows where the ID is equal or less than the value of the current row. Let us look at the execution plan:
What happens is that the database fetches all the rows from the table and using a nested loop, it again fetches the rows from which the sum is calculated. This can also be seen in the statistics:
Table ‘RunTotalTestData‘. Scan count 15, logical reads 30, physical reads 0...
Using join
Another variation is to use join. Now the query could look like:
--------------------------------------------------------------------
-- using join
--------------------------------------------------------------------
SELECT a.id, a.value, SUM(b.Value)
FROM RunTotalTestData a,
RunTotalTestData b
WHERE b.id <= a.id
GROUP BY a.id, a.value
ORDER BY a.id;
The results are the same but the technique is a bit different. Instead of fetching the sum for each row, the sum is created by using a GROUP BY
clause. The rows are cross joined restricting the join only to equal or smaller ID values in B. The plan:
The plan looks somewhat different and what actually happens is that the table is read only twice. This can be seen more clearly with the statistics.
Table ‘RunTotalTestData‘. Scan count 2, logical reads 31...
The correlated scalar query has a calculated cost of 0.0087873 while the cost for the join version is 0.0087618. The difference isn‘t much but then again it has to be remembered that we‘re playing with extremely small amounts of data.
Using conditions
In real-life scenarios, restricting conditions are often used, so how are conditions applied to these queries. The basic rule is that the condition must be defined twice in both of these variations. Once for the rows to fetch and the second time for the rows from which the sum is calculated.
If we want to calculate the running total for odd value numbers, the correlated scalar version could look like the following:
--------------------------------------------------------------------
-- correlated scalar, subset
--------------------------------------------------------------------
SELECT a.id, a.value, (SELECT SUM(b.value)
FROM RunTotalTestData b
WHERE b.id <= a.id
AND b.value % 2 = 1)
FROM RunTotalTestData a
WHERE a.value % 2 = 1
ORDER BY a.id;
The results are:
id value runningtotal
-- ----- ------------
1 1 1
4 7 8
5 9 17
7 13 30
11 57 87
13 59 146
And with the join version, it could be like:
--------------------------------------------------------------------
-- with join, subset
--------------------------------------------------------------------
SELECT a.id, a.value, SUM(b.Value)
FROM RunTotalTestData a,
RunTotalTestData b
WHERE b.id <= a.id
AND a.value % 2 = 1
AND b.value % 2 = 1
GROUP BY a.id, a.value
ORDER BY a.id;
When actually having more conditions, it can be quite painful to maintain the conditions correctly. Especially if they are built dynamically.
Calculating running totals for partitions of data
If the running total needs to be calculated to different partitions of data, one way to do it is just to use more conditions in the joins. For example, if the running totals would be calculated for both odd and even numbers, the correlated scalar query could look like:
--------------------------------------------------------------------
-- correlated scalar, partitioning
--------------------------------------------------------------------
SELECT a.value%2, a.id, a.value, (SELECT SUM(b.value)
FROM RunTotalTestData b
WHERE b.id <= a.id
AND b.value%2 = a.value%2)
FROM RunTotalTestData a
ORDER BY a.value%2, a.id;
The results:
even id value running total
---- -- ----- -------------
0 2 2 2
0 3 4 6
0 6 12 18
0 8 16 34
0 9 22 56
0 10 42 98
0 12 58 156
0 14 60 216
1 1 1 1
1 4 7 8
1 5 9 17
1 7 13 30
1 11 57 87
1 13 59 146
So now the partitioning condition is added to the WHERE
clause of the scalar query. When using the join version, it could be similar to:
--------------------------------------------------------------------
-- with join, partitioning
--------------------------------------------------------------------
SELECT a.value%2, a.id, a.value, SUM(b.Value)
FROM RunTotalTestData a,
RunTotalTestData b
WHERE b.id <= a.id
AND b.value%2 = a.value%2
GROUP BY a.value%2, a.id, a.value
ORDER BY a.value%2, a.id;
With SQL Server 2012
SQL Server 2012 makes life much more simpler. With this version, it‘s possible to define an ORDER BY
clause in the OVER
clause.
So to get the running total for all rows, the query would look:
--------------------------------------------------------------------
-- Using OVER clause
--------------------------------------------------------------------
SELECT a.id, a.value, SUM(a.value) OVER (ORDER BY a.id)
FROM RunTotalTestData a
ORDER BY a.id;
The syntax allows to define the ordering of the partition (which in this example includes all rows) and the summary is calculated in that order.
To define a condition for the data, it doesn‘t have to be repeated anymore. The running total for odd numbers would look like:
--------------------------------------------------------------------
-- Using OVER clause, subset
--------------------------------------------------------------------
SELECT a.id, a.value, SUM(a.value) OVER (ORDER BY a.id)
FROM RunTotalTestData a
WHERE a.value % 2 = 1
ORDER BY a.id;
And finally, partitioning would be:
--------------------------------------------------------------------
-- Using OVER clause, partition
--------------------------------------------------------------------
SELECT a.value%2, a.id, a.value, SUM(a.value) OVER (PARTITION BY a.value%2 ORDER BY a.id)
FROM RunTotalTestData a
ORDER BY a.value%2, a.id;
What about the plan? It‘s looking very different. For example, the simple running total for all rows looks like:
And the statistics:
Table ‘Worktable‘. Scan count 15, logical reads 85, physical reads 0...
Table ‘RunTotalTestData‘. Scan count 1, logical reads 2, physical reads 0...
Even though the scan count looks quite high at first glance, it isn‘t targeting the actual table but a worktable. The worktable is used to store intermediate results which are then read in order to create the calculated results.
The calculated cost for this query is now 0.0033428 while previously with the join version, it was 0.0087618. Quite an improvement.
References
- SUM (SQL Server 2008 R2)
- OVER (SQL Server 2008 R2)
- SUM (SQL Server ‘Denali‘)
- OVER (SQL Server ‘Denali‘)
from http://geekswithblogs.net/Rhames/archive/2008/10/28/calculating-running-totals-in-sql-server-2005---the-optimal.aspx
DECLARE @SalesTbl TABLE (DayCount smallint, Sales money, RunningTotal money)DECLARE @RunningTotal moneyINSERT INTO @SalesTblSET @RunningTotal = 0SELECT DayCount, Sales, nullFROM SalesORDER BY DayCountUPDATE @SalesTblSET @RunningTotal = RunningTotal = @RunningTotal + SalesFROM @SalesTblSELECT * FROM @SalesTbl
Method | Time Taken |
Nested sub-query | 9300 ms |
Self join | 6100 ms |
Cursor | 400 ms |
Update to local variable | 140 ms |
Note: There is a pretty big assumption in using the “Update to local variable” method. This is that the Update statement will update the rows in the temp table in the correct order. There is no simple way to specify the order for an Update statement, so potentially this method could fail, although I have not seen this actually happen yet!
I think that if I use a table variable, then the update will probably be in the correct order, because there are no indexes for the query optimizer to use, and parallellism will not occur. However, I can‘t be sure about this!
CREATE TABLE Sales (DayCount smallint, Sales money)CREATE CLUSTERED INDEX ndx_DayCount ON Sales(DayCount)goINSERT Sales VALUES (1,120)INSERT Sales VALUES (2,60)INSERT Sales VALUES (3,125)INSERT Sales VALUES (4,40)DECLARE @DayCount smallint, @Sales moneySET @DayCount = 5SET @Sales = 10WHILE @DayCount < 5000BEGININSERT Sales VALUES (@DayCount,@Sales)SET @DayCount = @DayCount + 1SET @Sales = @Sales + 15END
SELECT * FROM @SalesTb
参考 http://*.com/questions/860966/calculate-a-running-total-in-sqlserver
CTE:
with CTE_RunningTotal
as
(
select T.ord, T.total, T.total as running_total
from #t as T
where T.ord = 0
union all
select T.ord, T.total, T.total + C.running_total as running_total
from CTE_RunningTotal as C
inner join #t as T on T.ord = C.ord + 1
)
select C.ord, C.total, C.running_total
from CTE_RunningTotal as C
option (maxrecursion 0)
SQL Server 2012 Sum() Over()
select id,somedate,somevalue, sum(somevalue) over(order by somedate rows unbounded preceding) as runningtotal
from TestTable
Cross Apply: very simmilar to the correlated scalar query
select t.id,t.somedate,t.somevalue,rt.runningTotal
from TestTable t cross apply (select sum(somevalue) as runningTotal from TestTable where somedate <= t.somedate ) as rt
order by t.somedate
Calculating simple running totals in SQL Server,布布扣,bubuko.com