Pyramids
| Time Limit: 1000MS | Memory Limit: 65536K | |||
| Total Submissions: 3451 | Accepted: 1123 | Special Judge | ||
Description
Recently in Farland, a country in Asia, a famous scientist Mr. Log Archeo has discovered ancient pyramids. But unlike those in Egypt and Central America, they have triangular (not rectangular) foundation. That is, they are tetrahedrons in mathematical sense. In order to find out some important facts about the early society of the country (it is widely believed that the pyramid sizes are in tight connection with Farland ancient calendar), Mr. Archeo needs to know the volume of the pyramids. Unluckily, he has reliable data about their edge lengths only. Please, help him!
Input
The file contains six positive integer numbers not exceeding 1000 separated by spaces, each number is one of the edge lengths of the pyramid ABCD. The order of the edges is the following: AB, AC, AD, BC, BD, CD.
Output
A real number -- the volume printed accurate to four digits after decimal point.
Sample Input
1000 1000 1000 3 4 5
Sample Output
1999.9938
Source
Northeastern Europe 2002, Northern Subregion
| Problem: 2208 | ||
| Memory: 188K | Time: 47MS | |
| Language: C++ | Result: Accepted |
#include<iostream>
#include<algorithm>
#include<cmath>
#include<cstdio>
using namespace std;
//p,q,r为AD,BD,CD;n,l,m为AB,BC,AC;
double V_tetrahedron(double l, double m, double n, double q, double p, double r) {
//return sqrt((4 * p*p*q*q*r*r - p*p*(q*q + r*r - l*l)*(q*q + r*r - l*l) - q*q*(r*r + p*p - m*m)*(r*r + p*p - m*m) - r*r*(p*p + q*q - n*n)*(p*p + q*q - n*n) + (p*p + q*q - n*n)*(q*q + r*r - l*l)*(r*r + p*p - m*m))) / 12.0;
double x = q*q + r*r - l*l, y = r*r + p*p - m*m, z = p*p + q*q - n*n;
return sqrt(( * p*p*q*q*r*r - p*p*x*x - q*q*y*y - r*r*z*z + z*x*y)) / 12.0;
}
int main(){
double l,m,n,q,p,r;
cin>>n>>m>>p>>l>>q>>r;
double ans=V_tetrahedron(l,m,n,q,p,r);
printf("%.4lf\n",ans);
return ;
}