题目

数据

1.薪资累加、月份排名（降序）

select *,
sum(salary) over(partition by id order by month ) sum_salary, # order by记得排序，不然都是总和。
rank() over(partition by id order by `month` desc) rks  # 按月份排序,跳跃
from employee

2.去掉最近一个月的，因为月份是按照倒序，所以直接筛选排名第一的就好 ，接着就是按两个字段排序

SELECT t.id, t.`month`, t.sum_salary FROM
(

 SELECT id, `month`, salary,
 SUM(salary) over(PARTITION BY id ORDER BY `month` ROWS 2 PRECEDING) sum_salary, -- 累加的总薪水
 rank() over(PARTITION BY id ORDER BY `month` DESC) ranks   -- 排名好去掉最近一个月
 FROM employee
 
) t
WHERE t.ranks > 1
order by id ,`month` desc;