百度地图Api 根据两个坐标点计算距离

百度地图Android Sdk的Api里面,没有现成的直接获取两个坐标点之间距离的方法,但是,在jsapi里面,有直接计算距离的方法。

class Point:
pass def max(a,b):
if a>b:
return a
return b
def min(a,c):
if a>c:
return c
return a def lw(a, b, c):
# b != n && (a = Math.max(a, b));
# c != n && (a = Math.min(a, c));
a = max(a,b)
a = min(a,c)
return a def ew(a, b, c): while a > c:
a -= c - b
while a < b:
a += c - b
return a def oi(a):
return math.pi * a / 180 def Td(a, b, c, d):
return 6370996.81 * math.acos(math.sin(c) * math.sin(d) + math.cos(c) * math.cos(d) * math.cos(b - a)) def Wv(a, b):
if not a or not b:
return 0;
a.lng = ew(a.lng, -180, 180);
a.lat = lw(a.lat, -74, 74);
b.lng = ew(b.lng, -180, 180);
b.lat = lw(b.lat, -74, 74);
return Td(oi(a.lng), oi(b.lng), oi(a.lat), oi(b.lat)) def getDistance(a, b):
c = Wv(a, b);
return c

所以,根据上面的方法,我们把计算距离的方法用java语言实现如下:

    public static double getDistance(double lat_a, double lng_a, double lat_b, double lng_b){
double pk = 180 / 3.14169;
double a1 = lat_a / pk;
double a2 = lng_a / pk;
double b1 = lat_b / pk;
double b2 = lng_b / pk;
double t1 = Math.cos(a1) * Math.cos(a2) * Math.cos(b1) * Math.cos(b2);
double t2 = Math.cos(a1) * Math.sin(a2) * Math.cos(b1) * Math.sin(b2);
double t3 = Math.sin(a1) * Math.sin(b1);
double tt = Math.acos(t1 + t2 + t3);
return 6371000 * tt;
}

参考:

http://blog.csdn.net/mad1989/article/details/9933089

http://blog.csdn.net/pleasurelong/article/details/26855049

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