Problem
Given the head of a sorted linked list, delete all duplicates such that each element appears only once. Return the linked list sorted as well.
Constraints:
- The number of nodes in the list is in the range [0, 300].
- -100 <= Node.val <= 100
- The list is guaranteed to be sorted in ascending order.
Example1
Input: head = [1,1,2]
Output: [1,2]
Example2
Input: head = [1,1,2,3,3]
Output: [1,2,3]
Solution
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
if(!head || !head->next)
return head;
ListNode *cur = head;
while(cur)
{
ListNode *next = cur->next;
while(next && next->val == cur->val)
next = next->next;
cur->next = next;
cur = cur->next;
}
return head;
}
};