问题描述：

 

 

 代码展示：

 1 #include<stdio.h>
 2 #include<string.h>
 3 #include<ctype.h> 
 4 const char* rev="A   3  HIL JM O   2TUVWXY51SE Z  8 ";//注意空格数和非法镜像的个数对应
 5 const char* msg[] = {"not a palindrome","a regular palindrome","a mirrored string","a mirrored palindrome"}; 
 6 char r(char ch)
 7 {
 8     if(isalpha(ch))
 9         return rev[ch-'A'];    
10     return rev[ch-'0'+25];
11 }  
12 int main()
13 {
14     char s[30];    
15     while(scanf("%s",s) == 1)    
16     {
17         int len = strlen(s);
18         int p = 1,m = 1;
19         for(int i = 0;i<(len+1)/2;i++)
20         {
21             if(s[i] != s[len-1-i])  p=0;
22             if(r(s[i]) != s[len-1-i]) m=0;
23         }
24         printf("%s -- is %s.\n\n",s,msg[m*2+p]);
25     }
26     return 0;
27 }
28 //代码非原创 原文代码链接：https://blog.csdn.net/YeziTong/java/article/details/83899221

运行结果：