mysql用户自定义函数实例与部分问题解决方法

一、查看创建函数的功能是否开启:
mysql> show variables like ‘%func%‘;
+-----------------------------------------+-------+
| Variable_name                            | Value |
+-----------------------------------------+-------+
| log_bin_trust_function_creators | ON    |
+-----------------------------------------+-------+
1 row in set (0.02 sec)

二、如果Value处值为OFF,则需将其开启。
mysql> set global log_bin_trust_function_creators=1;

 
use app02
delimiter // 


mysql>DROP FUNCTION IF EXISTS `testhanshu`;

CREATE  FUNCTION `testhanshu`(`tustate` int)
 RETURNS varchar(2000)
BEGIN

declare oneAddr varchar(200) default ‘‘;
declare allAddr varchar(2000) default ‘‘;
DECLARE done INT DEFAULT FALSE;
 
declare  curl CURSOR for select utruename from tsys_user where ustate = tustate;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1; 
open curl;

REPEAT 
      FETCH curl INTO oneAddr; 
      IF NOT done THEN 
        set oneAddr = CONCAT(oneAddr, ‘;‘); 
        set allAddr = CONCAT(allAddr, oneAddr); 
      END IF; 
    UNTIL done END REPEAT;  


 close curl;
 RETURN allAddr;
END;

 

mysql>select testhanshu(1);

 

  在使用MySql自己定义的函数时,出现错误java.sql.SQLException: This function has none of DETERMINISTIC, NO SQL, or READS SQL DATA in its declaration and binary logging is enabled (you *might* want to use the less safe log_bin_trust_function_creators variable)

     解决办法有三种:

     1. 登录MySql客户端,执行: SET GLOBAL log_bin_trust_function_creators = 1;
     2.在登录MySQL服务器是,在服务启动时加上 “--log-bin-trust-function-creators=1 ”参数并设置为1。
     3.在my.ini(my.cnf)中的[mysqld]区段中加上 log-bin-trust-function-creators=1。

 

mysql用户自定义函数实例与部分问题解决方法

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