js与H5 canvas实现动态旋转圣诞树
效果图:
源代码
<canvas id="c" height="356" width="446"> <script> var collapsed = true; function toggle() { var fs = top.document.getElementsByTagName('frameset')[0]; var f = fs.getElementsByTagName('frame'); if (collapsed) { fs.rows = '250px,*'; fs.noResize = false; f[0].noResize = false; f[1].noResize = false; } else { fs.rows = '30px,*'; fs.noResize = true; f[0].noResize = true; f[1].noResize = true; } collapsed = !collapsed; } </script> <script> var b = document.body; var c = document.getElementsByTagName('canvas')[0]; var a = c.getContext('2d'); document.body.clientWidth; </script> <script> M = Math; Q = M.random; J = []; U = 16; T = M.sin; E = M.sqrt; for (O = k = 0; x = z = j = i = k < 200;) with (M[k] = k ? c.cloneNode(0) : c) { width = height = k ? 32 : W = 446; with (getContext('2d')) if (k > 10 | !k) for ( font = '60px Impact', V = 'rgba('; I = i * U, fillStyle = k ? k == 13 ? V + '205,205,215,.15)' : V + (147 + I) + ',' + (k % 2 ? 128 + I : 0) + ',' + I + ',.5)' : '#cca', i < 7;) beginPath(fill(arc(U - i / 3, 24 - i / 2, k == 13 ? 4 - (i++) / 2 : 8 - i++, 0, M.PI * 2, 1))); else for (; x = T(i), y = Q() * 2 - 1, D = x * x + y * y, B = E(D - x / .9 - 1.5 * y + 1), R = 67 * (B + 1) * (L = k / 9 + .8) >> 1, i++ < W; ) if (D < 1) beginPath(strokeStyle = V + R + ',' + (R + B * L >> 0) + ',40,.1)'), moveTo(U + x * 8, U + y * 8), lineTo(U + x * U, U + y * U), stroke(); for ( y = H = k + E(k++) * 25, R = Q() * W; P = 3, j < H;) J[O++] = [ x += T(R) * P + Q() * 6 - 3, y += Q() * U - 8, z += T(R - 11) * P + Q() * 6 - 3, j / H * 20 + ((j += U) > H & Q() > .8 ? Q(P = 9) * 4 : 0) >> 1] } setInterval(function G(m, l) { A = T(D - 11); if (l) return ( m[2] - l[2]) * A + (l[0] - m[0]) * T(D); a.clearRect(0, 0, W, W); J.sort(G); for ( i = 0; L = J[i++]; a.drawImage(M[L[3] + 1], 207 + L[0] * A + L[2] * T(D) >> 0, L[1] >> 1)) { if (i == 2e3) a.fillText ('Happy Christmas!', U, 345); if (!(i % 7)) a.drawImage(M[13], ((157 * (i * i) + T(D * 5 + i * i) * 5) % W) >> 0, ((113 * i + (D * i) / 60) % (290 + i / 99)) >> 0); } D += .02 }, 1) </script>