我使用以下代码打开了一个货架:
#!/usr/bin/python
import shelve #Module:Shelve is imported to achieve persistence
Accounts = 0
Victor = {'Name':'Victor Hughes','Email':'victor@yahoo.com','Deposit':65000,'Accno':'SA456178','Acctype':'Savings'}
Beverly = {'Name':'Beverly Dsilva','Email':'bevd@hotmail.com','Deposit':23000,'Accno':'CA432178','Acctype':'Current'}
def open_shelf(name='shelfile.shl'):
global Accounts
Accounts = shelve.open(name) #Accounts = {}
Accounts['Beverly']= Beverly
Accounts['Victor']= Victor
def close_shelf():
Accounts.close()
我能够将值附加到货架但无法修改值.
我已经定义了一个函数Deposit(),我想从中修改shelve中存在的数据.但是它给了我以下错误:
Traceback (most recent call last):
File "./functest.py", line 16, in <module>
Deposit()
File "/home/pavitar/Software-Development/Python/Banking/Snippets/Depositfunc.py", line 18, in Deposit
for key in Accounts:
TypeError: 'int' object is not iterable
这是我的功能:
#!/usr/bin/python
import os #This module is imported so as to use clear function in the while-loop
from DB import * #Imports the data from database DB.py
def Deposit():
while True:
os.system("clear") #Clears the screen once the loop is re-invoked
input = raw_input('\nEnter the A/c type: ')
flag=0
for key in Accounts:
if Accounts[key]['Acctype'].find(input) != -1:
amt = input('\nAmount of Deposit: ')
flag+=1
Accounts[key]['Deposit'] += amt
if flag == 0:
print "NO such Account!"
if __name__ == '__main__':
open_shelf()
Deposit()
close_shelf()
我是Python的新手.请帮忙.如果我错了,请更正我.我需要有人对这段代码的功能给出一些解释.我很困惑.
解决方法:
首先,不要使用全局帐户,而是来回传递它.使用全局导致您的错误.像这样:
def open_shelf(name='shelfile.shl'):
Accounts = shelve.open(name) #Accounts = {}
...
return Accounts
def close_shelf(Accounts):
Accounts.close()
def Deposit(Accounts):
...
if __name__ == '__main__':
Accounts = open_shelf()
Deposit(Accounts)
close_shelf(Accounts)
其次,不要重新定义内置函数.在Deposit()中,将raw_input的结果分配给名为input的变量:
input = raw_input('\nEnter the A/c type: ')
四行之后,您尝试使用内置输入功能:
amt = input('\nAmount of Deposit: ')
但这不起作用,因为输入已被重新定义!
第三,当迭代搁置物品时,遵循以下模式:1)抓住搁置物品,2)变异物品,3)将变异物品写回架子.像这样:
for key, acct in Accounts.iteritems(): # grab a shelved item
if val['Acctype'].find(input) != -1:
amt = input('\nAmount of Deposit: ')
flag+=1
acct['Deposit'] += amt # mutate the item
Accounts[key] = acct # write item back to shelf
(第三点建议是从hughdbrown的答案中调整过的.)