include <bits/stdc++.h>
using namespace std;
///继承vector解决位数限制,操作方便
struct Huge_Int:vector
static const int WIDTH = 4;///压位数
static const long long BASE = 1e4;///单位基
///初始化,同时也可以将低精度转高精度、字符串转高精度
///无需单独写高精度数和低精度数的运算函数,十分方便
Huge_Int(long long n = 0){
*this = n;
}
Huge_Int(const string &str){
*this = str;
}
///格式化,包括进位和去前导0,用的地方很多,先写一个
Huge_Int & format(){
while(!empty() && !back()) pop_back();//去除最高位可能存在的0
if(empty())return *this;
for(int i=1; i<size(); ++i)
{
(*this)[i]+=(*this)[i-1]/BASE;
(*this)[i-1]%=BASE;
}//位内进位
while(back()>=BASE)
{
push_back(back()/BASE);
(*this)[size()-2]%=BASE;
}//位外进位
return *this;//为使用方便,将进位后的自身返回引用
}
///重载等于,初始化、赋值、输入都用得到
Huge_Int operator=(long long n){
clear();
push_back(n);
format();
return *this;
}
Huge_Int operator=(const string &str){
clear();
if(str.empty()) push_back(0);
for(int i = str.length() - 1;i>=0;i-=WIDTH){
long long tmp = 0;
for(int j = max(i-WIDTH+1,0);j<=i;j++)
tmp = (tmp<<3) + (tmp<<1) + (str[j]^48);
push_back(tmp);
}
return *this;
}
///重载输入输出
friend istream & operator>>(istream &is, Huge_Int &tmp){
string str;
if(!(is>>str)) return is;
tmp = str;
return is;
}
friend ostream & operator<<(ostream &os, const Huge_Int &tmp){
if(tmp.empty()) os<<0;
else os<<tmp[tmp.size()-1];
for(int i = tmp.size() - 2;i>=0;i--){
os<<setfill('0')<<setw(WIDTH)<<tmp[i];
}
return os;
}
///重载逻辑运算符,只需要写两个,其他的直接代入即可
///常量引用当参数,避免拷贝更高效
friend bool operator!=(const Huge_Int &a,const Huge_Int &b){
if(a.size()!=b.size()) return 1;
for(int i=a.size()-1; i>=0; i--)
if(a[i]!=b[i]) return 1;
return 0;
}
friend bool operator==(const Huge_Int &a,const Huge_Int &b){
return !(a!=b);
}
friend bool operator<(const Huge_Int &a,const Huge_Int &b){
if(a.size()!=b.size()) return a.size()<b.size();
for(int i=a.size()-1; i>=0; i--)
if(a[i]!=b[i])return a[i]<b[i];
return 0;
}
friend bool operator>=(const Huge_Int &a,const Huge_Int &b){
return !(a<b);
}
friend bool operator>(const Huge_Int &a,const Huge_Int &b){
return b<a;
}
friend bool operator<=(const Huge_Int &a,const Huge_Int &b){
return !(a>b);
}
///加法,先实现+=,这样更简洁高效
friend Huge_Int & operator+=(Huge_Int &a,const Huge_Int &b){
if(a.size()<b.size()) a.resize(b.size());
for(int i=0; i!=b.size(); i++) a[i]+=b[i];//被加数要最大位,并且相加时不要用未定义区间相加
return a.format();
}
friend Huge_Int operator+(Huge_Int a,const Huge_Int &b){
return a+=b;
}
friend Huge_Int & operator++(Huge_Int &a){
return a+=1;
}
friend Huge_Int operator++(Huge_Int &a,int){
Huge_Int old = a;
++a;
return old;
}
///减法,返回差的绝对值,由于后面有交换,故参数不用引用
friend Huge_Int & operator-=(Huge_Int &a,Huge_Int b){
if(a<b){
Huge_Int t = a;
a = b;
b = t;
}
for(int i=0; i!=b.size(); a[i]-=b[i],i++){
if(a[i]<b[i]){//需要借位
int j=i+1;
while(!a[j]) j++;
while(j>i){
a[j--]--;
a[j]+=BASE;
}
}
}
return a.format();
}
friend Huge_Int operator-(Huge_Int a,const Huge_Int &b){
return a-=b;
}
friend Huge_Int & operator--(Huge_Int &a){
return a-=1;
}
friend Huge_Int operator--(Huge_Int &a,int){
Huge_Int old = a;
--a;
return old;
}
///乘法,不能先实现*=,因为是类多项式相乘,每位都需要保留,不能覆盖
friend Huge_Int operator*(const Huge_Int &a,const Huge_Int &b){
Huge_Int n;
n.assign(a.size()+b.size()-1,0);
for(int i=0; i!=a.size(); i++)
for(int j=0; j!=b.size(); j++)
n[i+j]+=a[i]*b[j];
return n.format();
}
friend Huge_Int & operator*=(Huge_Int &a,const Huge_Int &b){
return a=a*b;
}
///带余除法函数,方便除法和模运算,会改变a的值,所以先实现/尽量不多余地修改原来变量
///O(base/width*logn),待修改
friend Huge_Int divmod(Huge_Int &a,const Huge_Int &b){
Huge_Int ans;
for(int i=a.size()-b.size(); a>=b; i--){//减法代替除法
Huge_Int d;
d.assign(i+1,0);
d.back() = 1;
Huge_Int c=b*d;//提高除数位数进行减法
while(a>=c) a-=c,ans+=d;
}
return ans;
}
friend Huge_Int operator/(Huge_Int a,const Huge_Int &b){
return divmod(a,b);
}
friend Huge_Int & operator/=(Huge_Int &a,const Huge_Int &b){
return a = a/b;
}
friend Huge_Int & operator%=(Huge_Int &a,const Huge_Int &b){
divmod(a,b);
return a;
}
friend Huge_Int operator%(Huge_Int a,const Huge_Int &b){
return a%=b;
}
};
int main(){
std::ios::sync_with_stdio(0),cin.tie(0),cout.tie(0);
string n;
long long m;
cin>>n>>m;
Huge_Int a(n),b(m);
cout<<a<<endl
<<b<<endl
<<(a<b)<<endl
<<(a==b)<<endl
<<a+b<<endl
<<a-b<<endl
<<a*b<<endl
<<a/b<<endl
<<a%b<<endl;
++a+=b;
a++;
cout<<a<<endl;
--a-=b;
a--;
cout<<a<<endl;
return 0;
}