1027 Colors in Mars
part 1, 1.2
自己解法
#include <iostream>
using namespace std;
void printColor(int c)
{
int qu, re;
qu = c / 13;
re = c % 13;
char repColor[13] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C'};
cout << repColor[qu] << repColor[re];
}
int main()
{
int R, G, B;
cin >> R >> G >> B;
cout << "#";
printColor(R);
printColor(G);
printColor(B);
cout << endl;
system("pause");
return 0;
}
大神解法
- 柳神
#include <cstdio>
using namespace std;
int main() {
char c[14] = {"0123456789ABC"};
printf("#");
for(int i = 0; i < 3; i++) {
int num;
scanf("%d", &num);
printf("%c%c", c[num/13], c[num%13]);
}
return 0;
}
总结
- 很简单的一题了