简洁的标点符号并分成单词python

学习python目前还有一点问题.我试图从另一个子程序中取一条线并将其转换为单独的单词,除了少数几个之外,它们已经被删除了标点符号.该程序的输出应该是它显示的单词和行号.应该是这样的 – >字:[1]

输入文件:

please. let! this3 work.
I: hope. it works
and don't shut up

码:

    def createWordList(line):
        wordList2 =[]
        wordList1 = line.split()
        cleanWord = ""
        for word in wordList1: 
            if word != " ":
                for char in word:
                    if char in '!,.?":;0123456789':
                        char = ""
                    cleanWord += char
                    print(cleanWord," cleaned")
                wordList2.append(cleanWord)
         return wordList2

输出:

anddon't:[3]
anddon'tshut:[3]
anddon'tshutup:[3]
ihope:[2]
ihopeit:[2]
ihopeitworks:[2]
pleaselet:[1]
pleaseletthis3:[1]
pleaseletthis3work:[1]

我不确定这是由什么引起的,但我学会了Ada并在短时间内转换到python.

解决方法:

您应该将cleanWord设置回外部循环的每次迭代顶部的空字符串:

def createWordList(line):
    wordList2 =[]
    wordList1 = line.split()
    for word in wordList1:
        cleanWord = ""
        for char in word:
            if char in '!,.?":;0123456789':
                char = ""
            cleanWord += char
        wordList2.append(cleanWord)
    return wordList2

请注意,我还删除了if word!=“”,因为在line.split()之后你将永远不会有空格.

>>> createWordList('please. let! this3 work.')
['please', 'let', 'this', 'work']
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