用SBT和Play进行JSON序列化

用SBT和Play进行JSON序列化

本文主要讲述如何使用Play框架的JSON模块进行JSON的序列化和反序列化。

JSON数据是非常常见的数据类型,基本上做项目就离不开JSON。在Scala语言中,要处理JSON有多种方法,既可以利用Java相关的JSON库(比如Jackson或GSON)进行处理,又可以使用Scala语言的JSON库。那么,在这些库Spray JSON、Play JSON、Argonaut、Jackson、Rapture中,到底应该选择哪一个呢?

我分析了Scala领域的各种JSON库,最终决定使用Play JSON库作为我的首选工具。那么,怎样使用Play框架的JSON模块来完成任务,而无需引入整个Play框架呢?我找到了这个:Play JSON

一、Play JSON模块的使用

地址: http://mvnrepository.com/artifact/com.typesafe.play/play-json_2.11

当前Play JSON库的最新版本为2.4.3版。Maven库依赖如下:

com.typesafe.playplay-json_2.112.4.3

可以下载这个JAR包,并加到项目类路径下。也可以使用SBT管理SCala项目,在SBT文件中添加Play JSON依赖:

name := "proectj-name"
version := "1.0"
scalaVersion := "2.11.7"
libraryDependencies ++= Seq("com.typesafe.play" % "play-json_2.11" % "2.4.3") 

下面说明如何使用此库进行JSON的序列化和反序列化。

{
  "id": 1,
  "type": "credit card",
  "address": {
    "address1": "Baker str 3",
    "address2": "",
    "city": "London",
    "zipcode": "WC064"
  },
  "token": "u4lPaa74M"
  "cvv": 112
} 

以上是账单模型的一部分——支付。它是我们进行JSON序列化和反序列化的一部分。

二、创建模型

下面为JSON数据创建对应的对象模型。

1、Address字段

case class Address(address1: String,
                   address2: Option[String],
                   city: String,
                   state: String,
                   zipcode: String) 

2、声明读写规则

用于编写Scala模型到JSON的转换,以及从JSON读数据到Scala。这些逻辑可以在Address对象中进行声明:

object Address {
  import play.api.libs.json._
  implicit val addressFormats = Json.format[Address]
  def writeAddress(address: Address) = {
    Json.toJson(address)
  }
  def readAddress(jsonAddress: JsValue) = {
    jsonAddress.as[Address]
  }
} 

正如你看到的,我们使用了Play的对象Json,目的是实现对象的序列化和反序列化。我仅仅简单的使用了strings、numbers、arrays和null值类型。

3、在父对象执行动作

case class Payment(id: Long,
                   pType: String,
                   address: Address,
                   token: String,
                   cvv: String)
object Payment {
  import play.api.libs.json._
  def writePayment(payment: Payment) = {
    JsObject(Seq(
      "id" -> JsNumber(payment.id),
      "type" -> JsString(payment.pType),
      "address" -> Json.toJson(payment.address),
      "token" -> JsString(payment.token),
      "cvv" -> JsString(payment.cvv)
    ))
  }
  def readPayment(jsonPayment: JsValue) = {
    val id = (jsonPayment \ "id").as[Long]
    val pType = (jsonPayment \ "type").as[String]
    val address = (jsonPayment \ "address").as[Address]
    val token = (jsonPayment \ "token").as[String]
    val cvv = (jsonPayment \ "cvv").as[String]
    Payment(id, pType, address, token, cvv)
  }
} 

看上面的代码,由于type是Scala的关键字,故使用了pType作为变量代替。还有手动定义了支付对象的读写操作。

三、序列化实例

为了检查序列化是否正常工作,可以创建单元测试。在SBT文件中添加ScalaTest依赖,如下:

name := "proectj-name"
version := "1.0"
scalaVersion := "2.11.7"
libraryDependencies ++= Seq(
  "org.scalatest" % "scalatest_2.11" % "3.0.0-SNAP5" % "test",
  "com.typesafe.play" % "play-json_2.11" % "2.4.2") 

然后写支付的单元测试:

import models._
import models.Payment._
import org.scalatest._
import play.api.libs.json._
class PaymentTest extends FlatSpec with Matchers {
  val address = Address("1375 Burlingame Ave.", None, "Burlingame", "California", "94010")
  "Payment " should "be converted to JSON correctly " in {
    val payment = Payment(1, "creditCard", address, "wdweadowei3209423", "123")
    val paymentJSON = writePayment(payment)
    (paymentJSON \ ("id")).get should be (JsNumber(1))
    (paymentJSON \ ("type")).get should be (JsString("creditCard"))
    (paymentJSON \ ("address")).get should be (Json.toJson(payment.address))
    (paymentJSON \ ("token")).get should be (JsString("wdweadowei3209423"))
    (paymentJSON \ ("cvv")).get should be (JsString("123"))
  }
  it should " be deserialized correctly " in {
    val paymentJSON: JsValue = JsObject(Seq(
      "id" -> JsNumber(1),
      "type" -> JsString("creditCard"),
      "address" -> Json.toJson(address),
      "token" -> JsString("wdweadowei3209423"),
      "cvv" -> JsString("123")
    ))
    val payment = readPayment(paymentJSON)
    payment.id should be (1)
    payment.pType should be ("creditCard")
    payment.address should be (address)
    payment.token should be ("wdweadowei3209423")
    payment.cvv should be ("123")
  }
} 

四、总结

Play JSON库的功能足够强大,可以满足JSON相关的需求。要想了解更多内容,可以查看官方文档,见: 
https://www.playframework.com/documentation/2.4.x/ScalaJson


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