我正在尝试学习Java中的哈希映射和2D数组.我们有一个任务,因为有一个扫描仪接受一个字符串并将其转换为莫尔斯电码.我们使用的代码基于一个充满if语句的方法,但我想学习如何使用list,hashmaps或2D数组做这样的事情.我的代码如下:
import java.util.*;
public class MorseConversion
{
public static void main(String[] args)
{
Scanner userInput = new Scanner(System.in);
System.out.println("Please enter a phrase to convert to morse code: ");
String userString = userInput.nextLine();
System.out.println("");
System.out.println(stringConvert(userString));
}
public static String stringConvert(String userString)
{
String currentChar;
String getMorseChar;
String convertedString = "";
for (int i = 0; i < userString.length(); i++)
{
//Get character at i position
currentChar = userString.charAt(i) + "";
//convert character to morse code
getMorseChar = convert(currentChar);
//seperate words with the | symbol
if (getMorseChar.equals(" "))
{
convertedString = convertedString + " | ";
}
else
{
//concat the converted letter
convertedString = convertedString + getMorseChar;
//Add a space between each letter
if (!getMorseChar.equals(" "))
{
convertedString = convertedString + " ";
}
}
}
return convertedString;
}
public static String convert (String toEncode)
{
String morse = toEncode;
if (toEncode.equalsIgnoreCase("a"))
morse = ".-";
if (toEncode.equalsIgnoreCase("b"))
morse = "-...";
if (toEncode.equalsIgnoreCase("c"))
morse = "-.-.";
if (toEncode.equalsIgnoreCase("d"))
morse = "-..";
if (toEncode.equalsIgnoreCase("e"))
morse = ".";
if (toEncode.equalsIgnoreCase("f"))
morse = "..-.";
if (toEncode.equalsIgnoreCase("g"))
morse = "--.";
if (toEncode.equalsIgnoreCase("h"))
morse = "....";
if (toEncode.equalsIgnoreCase("i"))
morse = "..";
if (toEncode.equalsIgnoreCase("j"))
morse = ".---";
if (toEncode.equalsIgnoreCase("k"))
morse = "-.-";
if (toEncode.equalsIgnoreCase("l"))
morse = ".-..";
if (toEncode.equalsIgnoreCase("m"))
morse = "--";
if (toEncode.equalsIgnoreCase("n"))
morse = "-.";
if (toEncode.equalsIgnoreCase("o"))
morse = "---";
if (toEncode.equalsIgnoreCase("p"))
morse = ".--.";
if (toEncode.equalsIgnoreCase("q"))
morse = "--.-";
if (toEncode.equalsIgnoreCase("r"))
morse = ".-.";
if (toEncode.equalsIgnoreCase("s"))
morse = "...";
if (toEncode.equalsIgnoreCase("t"))
morse = "-";
if (toEncode.equalsIgnoreCase("u"))
morse = "..-";
if (toEncode.equalsIgnoreCase("v"))
morse = "...-";
if (toEncode.equalsIgnoreCase("w"))
morse = ".--";
if (toEncode.equalsIgnoreCase("x"))
morse = "-..-";
if (toEncode.equalsIgnoreCase("y"))
morse = "-.--";
if (toEncode.equalsIgnoreCase("z"))
morse = "--..";
if (toEncode.equalsIgnoreCase("0"))
morse = "-----";
if (toEncode.equalsIgnoreCase("1"))
morse = ".----";
if (toEncode.equalsIgnoreCase("2"))
morse = "..---";
if (toEncode.equalsIgnoreCase("3"))
morse = "...--";
if (toEncode.equalsIgnoreCase("4"))
morse = "....-";
if (toEncode.equalsIgnoreCase("5"))
morse = ".....";
if (toEncode.equalsIgnoreCase("6"))
morse = "-....";
if (toEncode.equalsIgnoreCase("7"))
morse = "--...";
if (toEncode.equalsIgnoreCase("8"))
morse = "---..";
if (toEncode.equalsIgnoreCase("9"))
morse = "----.";
if (toEncode.equalsIgnoreCase("."))
morse = ".-.-";
if (toEncode.equalsIgnoreCase(","))
morse = "--..--";
if (toEncode.equalsIgnoreCase("?"))
morse = "..--..";
return morse;
}
}
我出于好奇而严格地这样做.我已经把它砸到了我的脑海里,像这样的冗余是一个巨大的禁忌.提前致谢!
解决方法:
更简单的方法是使用初始化程序,使用字母作为键将字符加载到哈希映射中.然后,当您循环输入字符串中的字符时,您只需执行操作即可
在课程开始时做这样的事情:
private static HashMap<String, String> codes = new HashMap<String, String>();
static{
codes.put("a", ".-");
codes.put("b", "-...");
bla bla bla
}
然后在你的循环中
//convert character to morse code
getMorseChar = convert(currentChar);
你将会拥有
getMorseChar = code.get(currentChar.toLowerCase());
没有更讨厌的elseif声明.