SET @d0 = '2018-01-01';
SET @d1 = '2018-12-31';
SET @date = DATE_SUB(@d0, INTERVAL 1 DAY);

USE test;

CREATE TABLE aa_time_dim(
 DATE DATE DEFAULT NULL,
 id INT(11) NOT NULL,
 Y SMALLINT(6) DEFAULT NULL,
 m SMALLINT(6) DEFAULT NULL,
 d SMALLINT(6) DEFAULT NULL,
 yw SMALLINT(6) DEFAULT NULL,
 w SMALLINT(6) DEFAULT NULL,
 q SMALLINT(6) DEFAULT NULL,
 wd SMALLINT(6) DEFAULT NULL,
 m_name CHAR(10) DEFAULT NULL,
 wd_name CHAR(10) DEFAULT NULL,
 PRIMARY KEY (id))ENGINE = INNODB DEFAULT CHARSET = utf8;

SELECT * FROM aa_time_dim;

INSERT INTO aa_time_dim
SELECT 
    @date := DATE_ADD(@date, INTERVAL 1 DAY) AS DATE,
    DATE_FORMAT(@date, '%Y%m%d') AS id,
    YEAR(@date) AS Y,
    MONTH(@date) AS m,
    DAY(@date) AS d,
    DATE_FORMAT(@date, '%x') AS yw,
    WEEK(@date,3) AS w,
    QUARTER(@date) AS q,
    WEEKDAY(@date) + 1 AS wd,
    MONTHNAME(@date) AS m_name,
    DAYNAME(@date) AS wd_name
FROM xxx
WHERE DATE_ADD(@date,INTERVAL 1 DAY) <= @d1
ORDER BY DATE;

SELECT * FROM aa_time_dim;

DROP TABLE aa_time_dim;


---------------------

set @i = -1;

set @sql = repeat(" select 1 union all",-datediff('2021-01-01','2030-12-31')+1);

set @sql = left(@sql,length(@sql)-length(" union all"));

set @sql = concat("select date_add('2021-01-01',interval @i:=@i+1 day) as date from (",@sql,") as tmp");

prepare stmt from @sql;

execute stmt
---------------------
作者：longvs
来源：CSDN
原文：https://blog.csdn.net/longvs/article/details/22745433
版权声明：本文为博主原创文章，转载请附上博文链接！