1.
2.
运行结果相同
3.
生成了file.3,打开后视频无内容
4.
#include <stdio.h> #include <stdlib.h> #define N 10 typedef struct student { int num; char name[20]; int score; }STU; void sort(STU *pst, int n); int main() { FILE *fin; STU st[N]; int i; fin = fopen("file4.dat", "rb"); if( !fin ) { printf("fail to open file4.dat\n"); exit(0); } fread(st,sizeof(STU),N,fin); fclose(fin); for(i=0;i<N;i++) printf("%-6d%-10s%3d\n",st[i].num,st[i].name,st[i].score); return 0; }
#include <stdio.h> #include <string.h> #include<stdlib.h> const int N = 10; // 定义结构体类型struct student,并定义其别名为STU typedef struct student { long int id; char name[20]; float objective; /*客观题得分*/ float subjective; /*操作题得分*/ float sum; char level[10]; }STU; // 函数声明 void input(STU s[], int n); void output(STU s[], int n); void process(STU s[], int n); int main() { STU stu[N]; printf("录入%d个考生信息: 准考证号,姓名,客观题得分(<=40),操作题得分(<=60)\n", N); input(stu, N); printf("\n对考生信息进行处理: 计算总分,确定等级\n"); process(stu, N); printf("\n打印考生完整信息: 准考证号,姓名,客观题得分,操作题得分,总分,等级\n"); output(stu, N); return 0; } // 从文本文件examinee.txt读入考生信息:准考证号,姓名,客观题得分,操作题得分 void input(STU s[], int n) { FILE *fin; int i; fin=fopen("examinee.txt","r"); if(!fin) { printf("fail to open examinee.txt\n"); exit(0); } for(i=0;i<N;i++) fscanf(fin,"%d%s%f%f",&s[i].id,&s[i].name,&s[i].objective,&s[i].subjective); fclose(fin); } // 输出考生完整信息: 准考证号,姓名,客观题得分,操作题得分,总分,等级 // 不仅输出到屏幕上,还写到文本文件result.txt中 void output(STU s[], int n) { FILE *fout; int i; fout=fopen("result.txt","w"); if(!fout) { printf("fail to open result.txt\n"); exit(0); } for(i=0;i<N;i++) { printf("%-8d%-10s%-8.2f%-8.2f%-8.2f%s\n",s[i].id,s[i].name,s[i].objective,s[i].subjective,s[i].sum,s[i].level); fprintf(fout,"%-8d%-10s%-8.2f%-8.2f%-8.2f%s\n",s[i].id,s[i].name,s[i].objective,s[i].subjective,s[i].sum,s[i].level); } fclose(fout); } // 对考生信息进行处理:计算总分,排序,确定等级 void process(STU s[], int n) { STU t; int i,j; for(i=0;i<n;i++) { s[i].sum=s[i].objective+s[i].subjective; } for(i=0;i<n-1;i++) { for(j=i+1;j<n;j++) { if(s[i].sum<s[j].sum) { t=s[i]; s[i]=s[j]; s[j]=t; } } } for(i=0;i<n;i++) { if(i<n/10) strcpy(s[i].level,"优秀"); else if(i<n/2) strcpy(s[i].level,"合格"); else strcpy(s[i].level,"不合格"); } }