go语言fallthrough的用法心得

fallthrough:Go里面switch默认相当于每个case最后带有break,匹配成功后不会自动向下执行其他case,而是跳出整个switch, 但是可以使用fallthrough强制执行后面的case代码。

示例程序1:

switch {
case false:
fmt.Println("The integer was <= 4")
fallthrough
case true:
fmt.Println("The integer was <= 5")
fallthrough
case false:
fmt.Println("The integer was <= 6")
fallthrough
case true:
fmt.Println("The integer was <= 7")
fallthrough
case false:
fmt.Println("The integer was <= 8")
default:
fmt.Println("default case")
}

输出结果:

The integer was <= 5
The integer was <= 6
The integer was <= 7
The integer was <= 8

问题:是否在switch最后一个分支使用fallthrough???

go语言fallthrough的用法心得

有错误提示,显示:cannot fallthrough final case in switch

fallthrough不能用在switch的最后一个分支。

示例程序2:

上述示例是true、false常量进行分支判断,看如下变量示例。

s := "abcd"
switch s[1] {
case 'a':
fmt.Println("The integer was <= 4")
fallthrough
case 'b':
fmt.Println("The integer was <= 5")
fallthrough
case 'c':
fmt.Println("The integer was <= 6")
default:
fmt.Println("default case")
}

输出结果如下:

The integer was <= 5
The integer was <= 6

更改为:

s := "abcd"
switch s[3] {
case 'a':
fmt.Println("The integer was <= 4")
fallthrough
case 'b':
fmt.Println("The integer was <= 5")
fallthrough
case 'c':
fmt.Println("The integer was <= 6")
default:
fmt.Println("default case")
}

输出:

default case

总结:switch分支中使用变量进行判断的时,fallthrough正确的分支开始其作用。

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