Given an array A of integers, for each integer A[i] we may choose any x with -K <= x <= K, and add x to A[i].

After this process, we have some array B.

Return the smallest possible difference between the maximum value of B and the minimum value of B.

 

Example 1:

Input: A = [1], K = 0
Output: 0
Explanation: B = [1]

Example 2:

Input: A = [0,10], K = 2
Output: 6
Explanation: B = [2,8]

Example 3:

Input: A = [1,3,6], K = 3
Output: 0
Explanation: B = [3,3,3] or B = [4,4,4]

 

Note:

1. 1 <= A.length <= 10000
2. 0 <= A[i] <= 10000
3. 0 <= K <= 10000

class Solution {
    public int smallestRangeI(int[] A, int K) {
        Arrays.sort(A);
        int tmp = A[A.length - 1] - A[0];
        return tmp - 2 * K <= 0 ? 0 : tmp - 2 * K; 
    }
}

尼玛的，difference不能小于0哦