android – 在VideoView中播放流媒体,将网址转换为rtsp

2024-03-28 11:31:34

我需要以相同的布局播放youtube视频和录制视频.

为了执行此操作,我搜索youtube api,发现android版本需要高于2.2,这没关系,但是,我想使用VideoView.

我在这里看到一些关于这个问题的帖子,并决定最终使用此代码在VideoView中观看视频.

videoView = (VideoView) findViewById(R.id.your_video_view);

Log.d(TAG,getUrlVideoRTSP(current_url) + "  id yotube1  " );


//here type the url...
videoView.setVideoURI(Uri.parse(getUrlVideoRTSP(current_url)));



videoView.setMediaController(new MediaController(this)); //sets MediaController in the video view

videoView.requestFocus();//give focus to a specific view 
videoView.start();//starts the video

这段代码有效,但只需使用rtsp链接：

String exemple = "rtsp://v4.cache3.c.youtube.com/CjYLENy73wIaLQlW_ji2apr6AxMYDSANFEIJbXYtZ29vZ2xlSARSBXdhdGNoYOr_86Xm06e5UAw=/0/0/0/video.3gp";

我在url中有多个链接因此我需要代码将url转换为RTSP,我不能手动执行此操作,我检查一些代码并且所有代码都不起作用…

我试试这个：从这里开始
How to get RTSP URL?

public static String getUrlVideoRTSP(String urlYoutube)
{
    try
    {
        String gdy = "http://gdata.youtube.com/feeds/api/videos/";
        DocumentBuilder documentBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
        String id = extractYoutubeId(urlYoutube);
        URL url = new URL(gdy + id);
        HttpURLConnection connection = (HttpURLConnection) url.openConnection();
        Document doc = documentBuilder.parse(connection.getInputStream());
        Element el = doc.getDocumentElement();
        NodeList list = el.getElementsByTagName("media:content");///media:content
        String cursor = urlYoutube;
        for (int i = 0; i < list.getLength(); i++)
        {
            Node node = list.item(i);
            if (node != null)
            {
                NamedNodeMap nodeMap = node.getAttributes();
                HashMap<String, String> maps = new HashMap<String, String>();
                for (int j = 0; j < nodeMap.getLength(); j++)
                {
                    Attr att = (Attr) nodeMap.item(j);
                    maps.put(att.getName(), att.getValue());
                }
                if (maps.containsKey("yt:format"))
                {
                    String f = maps.get("yt:format");
                    if (maps.containsKey("url"))
                    {
                        cursor = maps.get("url");
                    }
                    if (f.equals("1"))
                        return cursor;
                }
            }
        }
        return cursor;
    }
    catch (Exception ex)
    {
        Log.e("Get Url Video RTSP Exception======>>", ex.toString());
    }
    return urlYoutube;

}



protected static String extractYoutubeId(String url) throws MalformedURLException
{
    String id = null;
    try
    {
        String query = new URL(url).getQuery();
        if (query != null)
        {
            String[] param = query.split("&");
            for (String row : param)
            {
                String[] param1 = row.split("=");
                if (param1[0].equals("v"))
                {
                    id = param1[1];
                }
            }
        }
        else
        {
            if (url.contains("embed"))
            {
                id = url.substring(url.lastIndexOf("/") + 1);
            }
        }
    }
    catch (Exception ex)
    {
        Log.e("Exception", ex.toString());
    }
    return id;
}

我使用上面这样的方法：

getUrlVideoRTSP(current_url)

当currnt_url要测试时：

current_url = "http://m.youtube.com/#/watch?v=FlsBObg-1BQ"

我尝试这个代码,它不起作用

private  class Syncyoutube extends AsyncTask <Void , Void , Void>{

@Override
    protected void onPostExecute(Void result) {
        // TODO Auto-generated method stub
        super.onPostExecute(result);
        /**
        videoView.setMediaController(new MediaController(this)); //sets MediaController in the video view
        //   MediaController containing controls for a MediaPlayer                                  
        videoView.requestFocus();//give focus to a specific view 
        videoView.start();//starts the video
        */
    }


public String getRstpLinks(String code){
    String[] urls = new String[3];
    String link = "http://gdata.youtube.com/feeds/api/videos/" + code + "?alt=json";
    String json = getJsonString(link); // here you request from the server
    try {
        JSONObject obj = new JSONObject(json);
        String entry = obj.getString("entry");
        JSONObject enObj = new JSONObject(entry);
        String group = enObj.getString("media$group");
        JSONObject grObj = new JSONObject(group);
        String content = grObj.getString("media$content");
        JSONObject cntObj = new JSONObject(group);
        JSONArray array = grObj.getJSONArray("media$content");
        for(int j=0; j<array.length(); j++){
            JSONObject thumbs = array.getJSONObject(j);
            String url = thumbs.getString("url");
            urls[j] = url;
            Log.d(TAG, url);
            //data.setThumbUrl(thumbUrl);
        }


        Log.v(TAG, content);
    } catch (Exception e) {
        Log.e(TAG, e.toString());
        urls[0] = urls[1] = urls[2] = null;
    }
    return urls[2];

}


public String getJsonString(String url){
    Log.e("Request URL", url);
    StringBuilder buffer = new StringBuilder();
    HttpClient client = new DefaultHttpClient();
    HttpGet     request = new HttpGet( url );
    HttpEntity entity = null;
    try {
        HttpResponse response = client.execute(request);

        if( response.getStatusLine().getStatusCode() == 200 ){
            entity = response.getEntity();
            InputStream is = entity.getContent();
            BufferedReader br = new BufferedReader(new InputStreamReader(is));
            String line = null;
            while( (line = br.readLine() )!= null ){
                buffer.append(line);
            }
            br.close();

        }
    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }finally{
        try {
            entity.consumeContent();
        } catch (Exception e) {
            Log.e(TAG, "Exception = " + e.toString() );
        }
    }

    return buffer.toString();
}





@Override
protected Void doInBackground(Void... params) {
    // TODO Auto-generated method stub


    code = id_current_url(current_url);
    //here type the url...
    String rstp_url = getRstpLinks(code);


    videoView.setVideoURI(Uri.parse(rstp_url));

     // the code crech in this line because null exeption
     // i chack this and discover that code variable is =tFXS9krT2VY , ok..
     // but rstp_url variable in null 

    Log.d(TAG,getRstpLinks(code) + "   idan id yotube1  " );
    return null;
}


}





public String id_current_url (String url) {

    String c_id = null ;

     c_id = url.substring((url.lastIndexOf("=")), url.length());

    return c_id ;
}   













}

代码崩溃在“videoView.setVideoURI(Uri.parse(rstp_url));”行因为null exeption
我查这个并发现代码变量= tFXS9krT2VY,好吧..
但是rstp_url变量为null

UdayKiran将这个答案写成类似的Q,有人可以解释他的意思吗？
我不明白他的回答

他的回答是：

Element rsp = (Element)entry.getElementsByTagName("media:content").item(1);

                              String anotherurl=rsp.getAttribute("url");

在gdata api中我们只有这种类型的链接：rtsp：//v3.cache7.c.youtube.com/CiILENy73wIaGQlOCTh0GvUeYRMYDSANFEgGUgZ2aWRlb3MM/0/0/0/video.3gp

这些是在VideoView中播放.

最后,我不使用此代码和视频浏览

我使用youtube android api,它的工作来自android 2.2而不是4.2就像我一样
在我的Q中写道,这是奶油.

使用rtsp的结果是视频质量差,需要处理宽高比.

解决方法:

以下适用于我：
在你的情况下代码= FlsBObg-1BQ.
你将获得很多网址,我选择返回最好的质量.

private String getRstpLinks(String code){
    String[] urls = new String[3];
    String link = "http://gdata.youtube.com/feeds/api/videos/" + code + "?alt=json";
    String json = getJsonString(link); // here you request from the server
    try {
        JSONObject obj = new JSONObject(json);
        String entry = obj.getString("entry");
        JSONObject enObj = new JSONObject(entry);
        String group = enObj.getString("media$group");
        JSONObject grObj = new JSONObject(group);
        String content = grObj.getString("media$content");
        JSONObject cntObj = new JSONObject(group);
        JSONArray array = grObj.getJSONArray("media$content");
        for(int j=0; j<array.length(); j++){
            JSONObject thumbs = array.getJSONObject(j);
            String url = thumbs.getString("url");
            urls[j] = url;
            Log.d(TAG, url);
            //data.setThumbUrl(thumbUrl);
        }


        Log.v(TAG, content);
    } catch (Exception e) {
        Log.e(TAG, e.toString());
        urls[0] = urls[1] = urls[2] = null;
    }
    return urls[2];

}

getJsonString()方法.

public static String getJsonString(String url){
    Log.e("Request URL", url);
    StringBuilder buffer = new StringBuilder();
    HttpClient client = new DefaultHttpClient();
    HttpGet     request = new HttpGet( url );
    HttpEntity entity = null;
    try {
        HttpResponse response = client.execute(request);

        if( response.getStatusLine().getStatusCode() == 200 ){
            entity = response.getEntity();
            InputStream is = entity.getContent();
            BufferedReader br = new BufferedReader(new InputStreamReader(is));
            String line = null;
            while( (line = br.readLine() )!= null ){
                buffer.append(line);
            }
            br.close();

        }
    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }finally{
        try {
            entity.consumeContent();
        } catch (Exception e) {
            Log.e(TAG, "Exception = " + e.toString() );
        }
    }

    return buffer.toString();
}

由于网络请求,不要忘记将其包装在异步任务中.

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