Python中多个列表与字典的合并方法
1多列表的合并
1）a+=b
a=['','','']
b = ['','','']
a += b
print(a) >>>['','','','','','']
2) a.extend(b)
a=['','','']
b = ['','','']
a.extend(b)
print(a)
>>>['1','2','3','22','55','66']
3) a[0:0] = b切片的方法
a=['','','']
b = ['','','']
a[len(a):len(a)] = b
print(a) >>>['','','','','','']
2 多字典的合并
1） dict(a,**b)
A = {'a' :1,'b':2,'c':3}
B = {'h':55,'s':66,'d':88}
C = dict(A,**B)
print(C)
>>>{'a' :1,'b':2,'c':3,'h':55,'s':66,'d':88}
2) dict(a.items()+b.items())
A = {'a' :1,'b':2,'c':3}
B = {'h':55,'s':66,'d':88}
C = dict(A.items()+B.items())print(C)
>>>{'a' :1,'b':2,'c':3,'h':55,'s':66,'d':88}
3）c = {} c.update(a) c.update(b)
A = {'a' :1,'b':2,'c':3}
B = {'h':55,'s':66,'d':88}
C = {}
C.update(A)
C.update(B)
print(C)
>>>{'a' :1,'b':2,'c':3,'h':55,'s':66,'d':88}