python day08作业答案

1.
a
f=open('11.txt','r',encoding='utf-8')
a=f.read()
print(a)
f.flush()
f.close()
b.
f=open('11.txt','a',encoding='utf-8')
f.write('信不信由你')
f.flush()
f.close()
c.
f=open('11.txt','r+',encoding='utf-8')
a=f.read()
print(a)
f.write('信不信由你')
f.flush()
f.close()
d.
f=open('11.txt','w',encoding='utf-8')
f.write('每天坚持一点')
f.flush()
f.close()
e.
f1=open('11.txt','r',encoding='utf-8')
f2=open('11.1','w',encoding='utf-8')
a=f1.readline()
b=f1.readline()
c=f1.readline()
d=f1.readline()
f2.write(a)
f2.write(b)
f2.write(c)
f2.write('你们就信了吧。')
f2.write(d) 2.
a,b
with open('t1.txt','r+',encoding='utf-8') as f1:
a=f1.read()
f1.write('a')
for line in a:
print(line)
c.
with open('t1.txt','r',encoding='utf-8') as f1:
a=f1.readlines()
for line in a:
print(line)
d.
with open('t1.txt','r',encoding='utf-8') as f1:
a=f1.read(4)
print(a) e.
with open('t1.txt','r',encoding='utf-8') as f1:
a=f1.readline()
a.replace(' ','')
a.replace('/n','')
print(a)
f.
with open('t1.txt','r',encoding='utf-8') as f1:
a=f1.readline()
b=f1.readline()
c=f1.readline()
print(c) g.
with open('t1.txt','a+',encoding='utf-8') as f1: f1.write('老男孩教育')
f1.seek(0)
a=f1.read()
print(a) h.
with open('t1.txt','r',encoding='utf-8') as f1:
a = f1.read()
print(a)
3.
b=[]
with open('a.txt','r',encoding='utf-8') as f1:
df=f1.readlines()
for i in range(0,len(df)):
a = {}
a['name']=df[i].replace('\n','').split(' ')[0]
a['price'] = df[i].replace('\n','').split(' ')[1]
a['amount'] = df[i].replace('\n','').split(' ')[2]
b.append(a)
print(b) 4.
f1= open('4.txt','r',encoding='utf-8')
f2=open('4.1.txt','w+',encoding='utf-8')
a=f1.read()
c=a.replace('alex','SB')
f2.write(c)
5.
lst=[]
f1= open('a.txt','r',encoding='utf-8')
for i in f1:
lst1=i.split()
print(lst1)
dic={}
dic[lst1[0].split(':')[0]]=lst1[0].split(':')[1]
dic[lst1[1].split(':')[0]]=lst1[1].split(':')[1]
dic[lst1[2].split(':')[0]] =lst1[2].split(':')[1]
dic[lst1[3].split(':')[0]] = lst1[3].split(':')[1]
lst.append(dic)
print(lst)
6.
lst=[]
f1= open('a.txt','r',encoding='utf-8')
a=f1.readline().split()
print(a)
for i in f1:
dic={}
print(i)
dic[a[0]]=i.split()[0]
dic[a[1]]=i.split()[1]
dic[a[2]]=i.split()[2]
lst.append(dic)
print(lst)
上一篇:python day09作业


下一篇:python day07作业答案