需要有关将具有以下结构的ISO 8601日期转换为javascript的帮助/提示.

CCYY-MM-DDThh:mm:ssTZD

我想照这样的日期：

January 28, 2011 - 7:30PM EST

我想让这个解决方案尽可能干净简洁.

解决方法:

datejs可以解析以下内容,您可能想尝试一下.

Date.parse('1997-07-16T19:20:15')           // ISO 8601 Formats
Date.parse('1997-07-16T19:20:30+01:00')     // ISO 8601 with Timezone offset

编辑：正则表达式版本

x = "2011-01-28T19:30:00EST"

MM = ["January", "February","March","April","May","June","July","August","September","October","November", "December"]

xx = x.replace(
    /(\d{4})-(\d{2})-(\d{2})T(\d{2}):(\d{2}):\d{2}(\w{3})/,
    function($0,$1,$2,$3,$4,$5,$6){
        return MM[$2-1]+" "+$3+", "+$1+" - "+$4%12+":"+$5+(+$4>12?"PM":"AM")+" "+$6
    }
)

结果

January 28, 2011 - 7:30PM EST

Edit2：我把我的时区改为EST,现在我跟进了

x = "2011-01-28T19:30:00-05:00"

MM = {Jan:"January", Feb:"February", Mar:"March", Apr:"April", May:"May", Jun:"June", Jul:"July", Aug:"August", Sep:"September", Oct:"October", Nov:"November", Dec:"December"}

xx = String(new Date(x)).replace(
    /\w{3} (\w{3}) (\d{2}) (\d{4}) (\d{2}):(\d{2}):[^(]+\(([A-Z]{3})\)/,
    function($0,$1,$2,$3,$4,$5,$6){
        return MM[$1]+" "+$2+", "+$3+" - "+$4%12+":"+$5+(+$4>12?"PM":"AM")+" "+$6 
    }
)

返回

January 28, 2011 - 7:30PM EST

基本上

String(new Date(x))

返回

Fri Jan 28 2011 19:30:00 GMT-0500 (EST)

正则表达式部分只是将上面的字符串转换为您需要的格式.

January 28, 2011 - 7:30PM EST