我试图从两个联接表中获取数据,从一个表中我收集列表标题,从第二个联接表中我收集列表数据.

型号代码：

function view_searching_type_items()
{
  $this->db->select("searching_type.searchtype_name, search_type_item.st_item_id_pk, search_type_item.searchtype_itemname");
  $this->db->from('searching_type');
  $this->db->join('search_type_item', 'search_type_item.st_id_fk = searching_type.st_id_pk');
  $query = $this->db->get();
  return $query->result_array(); 
}

控制器：

$url1 = 'http://localhost/pakistanmenu/index.php/Restaurant/ViewSearchingTypeItems';
    $curl_hand = curl_init($url1);
    curl_setopt($curl_hand, CURLOPT_TIMEOUT, 5);
    curl_setopt($curl_hand, CURLOPT_CONNECTTIMEOUT, 5);
    curl_setopt($curl_hand, CURLOPT_RETURNTRANSFER, true);
    $data1 = curl_exec($curl_hand);// json_decode($data)
    curl_close($curl_hand);
    $result['searchingtype'] = (array) json_decode($data1,true);

    $this->load->view('header');
    $this->load->view('index',$result);
    $this->load->view('footer');

查看代码：

<?php foreach ($searchingtype as $searchingtyp):?>

 <ul class="list-group checked-list-box">
    <h1 class="page-header leftsidebar-heading"><?php echo $searchingtyp['searchtype_name'];?></h1>

     <li class="list-group-item" data-style="button" style="cursor: pointer;">
         <span class="state-icon glyphicon glyphicon-unchecked">

         </span>

         <?php echo $searchingtyp['searchtype_itemname'];?>

         <input type="checkbox" class="hidden">

     </li>

请检查下面的图像,我已经显示了此代码的输出,并且我还画了我需要的输出,谢谢,请帮助我.谢谢

解决方法:

只需存储您的姓氏,并且仅在新名称与其不同时才打印它.发生这种情况时,我们还将创建新列表,以便每个组具有不同的列表.

<?php 
// Define our test variable
$lastName = null;

foreach ($searchingtype as $searchingtyp):
?>

    <?php 
    if ($lastName != $searchingtyp['searchtype_name']): 
        // It's not the same name
        if ($lastName != null):
            // Close the previous list (except from the first iteration).
        ?>
            </ul>
        <?php
        endif;
        ?>

     ?>
        <ul class="list-group checked-list-box">
            <li><h1 class="page-header leftsidebar-heading"><?php echo $searchingtyp['searchtype_name'];?></h1></li>
    <?php 
        // Store the current name so we can check again in the next iteration
        $lastName = $searchingtyp['searchtype_name'];
    endif;
    ?>

// The rest of your code.. just move the </ul> after the loop.

<?php endforeach ?>

</ul>