BZOJ 1084 最大子矩阵

http://www.lydsy.com/JudgeOnline/problem.php?id=1084

思路:分m=1和m=2操作

 #include<algorithm>
#include<cstdio>
#include<cmath>
#include<cstring>
#include<iostream>
int f[][],F[][][];
int sum[],sum1[],sum2[],n,m,K;
int read(){
int t=,f=;char ch=getchar();
while (ch<''||ch>''){if (ch=='-') f=-;ch=getchar();}
while (''<=ch&&ch<=''){t=t*+ch-'';ch=getchar();}
return t*f;
}
void sxpianfen1(){
for (int i=;i<=n;i++)
{int x=read();sum[i]=sum[i-]+x;}
for (int i=;i<=n;i++)
for (int k=;k<=K;k++){
f[i][k]=f[i-][k];
for (int j=;j<i;j++)
f[i][k]=std::max(f[i][k],f[j][k-]+sum[i]-sum[j]);
}
printf("%d\n",f[n][K]);
}
void sxpianfen2(){
for (int i=;i<=n;i++){
int x=read(),y=read();
sum1[i]=sum1[i-]+x;
sum2[i]=sum2[i-]+y;
}
for (int k=;k<=K;k++)
for (int i=;i<=n;i++)
for (int j=;j<=n;j++){
F[i][j][k]=std::max(F[i-][j][k],F[i][j-][k]);
for (int l=;l<i;l++) F[i][j][k]=std::max(F[i][j][k],F[l][j][k-]+sum1[i]-sum1[l]);
for (int l=;l<j;l++) F[i][j][k]=std::max(F[i][j][k],F[i][l][k-]+sum2[j]-sum2[l]);
if (i==j)
for (int l=;l<i;l++) F[i][j][k]=std::max(F[i][j][k],F[l][l][k-]+sum1[i]+sum2[j]-sum1[l]-sum2[l]);
}
printf("%d\n",F[n][n][K]);
}
int main(){
n=read();m=read();K=read();
if (m==){
sxpianfen1();
}else
sxpianfen2();
}
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