题意:
T个测试数据
n个数 q个查询
n个数 ( 下标从0开始)
Q u v 查询 [u, v ] 区间最长连续上升子序列
U u v 把u位置改成v
#include<iostream>
#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
#define N 101010
#define L(x) (x<<1)
#define R(x) (x<<1|1)
inline int Max(int a,int b){return a>b?a:b;}
inline int Min(int a,int b){return a<b?a:b;} struct node
{
int l,r;
int mid(){ return (l+r)>>1; }
int len(){ return r-l+1; }
int Llen, Rlen, maxlen; }tree[4*N];
int a[N];
void updata_up(int id){
tree[id].Llen = tree[L(id)].Llen;
tree[id].Rlen = tree[R(id)].Rlen;
tree[id].maxlen = Max( tree[L(id)].maxlen, tree[R(id)].maxlen); if( a[ tree[L(id)].r ] < a[ tree[R(id)].l ] )
{
if( tree[L(id)].Llen == tree[L(id)].len())
{
tree[id].Llen += tree[R(id)].Llen;
tree[id].maxlen = Max( tree[id].maxlen, tree[id].Llen);
}
if( tree[R(id)].Rlen == tree[R(id)].len() )
{
tree[id].Rlen += tree[L(id)].Rlen;
tree[id].maxlen = Max( tree[id].maxlen, tree[id].Rlen);
}
tree[id].maxlen = Max( tree[id].maxlen, tree[L(id)].Rlen + tree[R(id)].Llen ); } }
void build(int l, int r, int id){
tree[id].l = l, tree[id].r = r; if(l==r){ tree[id].Llen = tree[id].Rlen = tree[id].maxlen =1; return ; } int mid = (l+r)>>1;
build(l, mid, L(id));
build(mid+1, r, R(id));
updata_up(id);
} void updata(int pos,int id){
if(tree[id].l == tree[id].r)return ; int mid = tree[id].mid();
if( pos <= mid ) updata(pos, L(id));
else updata(pos, R(id));
updata_up(id);
} int query(int l, int r, int id){
if( l == tree[id].l && tree[id].r == r)
return tree[id].maxlen; int mid = tree[id].mid();
if(r <= mid)return query(l, r, L(id));
else if(mid < l) return query(l, r, R(id)); int L = query(l, mid, L(id)), R = query(mid+1, r, R(id)); if( a[mid] < a[mid+1] ){
int LL = Min( mid - l + 1, tree[L(id)].Rlen);
int RR = Min( r - mid, tree[R(id)].Llen);
return Max( Max(L,R), LL+RR);
}
else return Max(L, R);
} int main(){
int T,n,q,i; scanf("%d",&T);
while(T--){
scanf("%d %d", &n, &q);
for(i=1;i<=n;i++)scanf("%d",&a[i]); build(1, n, 1);
while(q--)
{
char c = '-';
while(c!='Q' && c!='U') c = getchar();
int u,v; scanf("%d %d", &u, &v); if(c == 'Q')
printf("%d\n", query(u+1, v+1, 1));
else if(c == 'U')
{ a[u+1] = v; updata(u+1, 1); } }
}
return 0;
}
/*
99
10 10
7 7 3 3 5 9 9 8 1 8
Q 6 6
U 3 4
Q 0 1
Q 0 5
Q 4 7
Q 3 5
Q 0 2
Q 4 6
U 6 10
Q 0 9 10 99
1 2 3 4 5 6 7 8 9 10
Q 4 7
U 0 8
Q 0 9
U 8 8 Q 0 9 */