L1-041 寻找250 (10分)

https://pintia.cn/problem-sets/994805046380707840/problems/994805089657536512

#include <cstdio>
#include <iostream>
using namespace std;
int main()
{
	int n,flag=0;
	int num=1;
	int value;
	while(scanf("%d",&n)!=EOF){   //这里还可以写成①cin>>n  ②~scanf("%d",&n)
		if(n==250&&flag==0)
		{
			value=num;
			flag=1;
		}
		num++;
	}
	cout<<value<<endl;
	return 0;
}

L1-039 古风排版 (20分)

https://pintia.cn/problem-sets/994805046380707840/problems/994805091888906240

#include <cstdio>
#include <iostream>
#include <cstring>
#include <string>
using namespace std;
int main()
{
	int n,len=0,i,x,j;
	char chr[1100];
	memset(chr,0,sizeof(chr));
	cin>>n;
	getchar();  //这一步不要忘了
	while((chr[len]=getchar())!='\n') {len++;}
	if(len%n!=0) {
	for(i=0,x=len;i<n-len%n;i++) chr[x++]=' ';}
	else x=len;
	for(i=0;i<n;i++)
	{
		for(j=x/n-1;j>=0;j--)
		{
			printf("%c",chr[j*n+i]);
		}
		cout<<endl;
	 } 
	 return 0;
}