C++ 高精度
高精度乘法:
#include <iostream>
#include <cstring>
using namespace std;
//定义变量
const int N = 1e6 + 10;
string s1 , s2;
int m = 0;
int a[N] , b[N] , c[N];
int lena , lenb , lenc;
int main()
{
//初始化赋值
memset(a , 0 , sizeof(a));
memset(b , 0 , sizeof(b));
memset(c , 0 , sizeof(c));
getline(cin , s1);
getline(cin , s2);
//定义两数值长度
lena = s1.length();
lenb = s2.length();
//赋值
for(int i = 1 ; i <= lena ; i++)
{
a[i] = s1[lena - i] - '0';
}
for(int i = 1 ; i <= lenb ; i++)
{
b[i] = s2[lenb - i] - '0';
}
for(int i = 1 ; i <= lena ; i++)
{
m = 0;
//错位相加
for(int j = 1 ; j <= lenb ; j++)
{
//当前乘积加上上次乘积的进位再加上原有数
c[i + j - 1] = a[i] * b[j] + m + c[i + j - 1];
//m为进位
m = c[i + j - 1] / 10;
//保存下来的数值
c[i + j - 1] %= 10;
}
//往前进一位
c[i + lenb] = m;
}
//两数相乘的积最大为两数的长度相加,两位数乘以两位数最大为四位数
lenc = lena + lenb;
//去掉结果前面多余的0
while(c[lenc] == 0 && lenc > 1)
{
lenc--;
}
for(int i = lenc ; i > 0 ; i--)
{
cout << c[i];
}
return 0;
}
高精度加法:
#include <iostream>
#include <cstring>
using namespace std;
const int N = 1e6 + 10;
int sa[N] , sb[N] , sc[N];
int m = 0;
int main()
{
memset(sa , 0 , sizeof(sa));
memset(sb , 0 , sizeof(sb));
memset(sc , 0 , sizeof(sc));
string a , b;
cin >> a >> b;
int lena , lenb , lenc;
lena = a.size() , lenb = b.size();
for(int i = 1 ; i <= lena ; i++)
{
sa[i] = a[lena - i] - '0';
}
for(int i = 1 ; i <= lenb ; i++)
{
sb[i] = b[lenb - i] - '0';
}
lenc = max(lena , lenb);
for(int i = 1 ; i <= lenc ; i++)
{
sc[i] = (m + sa[i] + sb[i]) % 10;
m = (m + sa[i] + sb[i]) / 10;
}
if(m != 0)
{
sc[++lenc] = 1;
}
while(sc[lenc] == 0 && lenc > 1)
{
lenc--;
}
for(int i = lenc ; i > 0 ; i--)
{
cout << sc[i];
}
return 0;
}
高精度减法:
#include <iostream>
#include <cstring>
using namespace std;
const int N = 1e6 + 10;
int a[N] , b[N];
int main()
{
memset(a , 0 , sizeof(a));
memset(b , 0 , sizeof(b));
string s1 , s2 , s3;
int lena , lenb;
getline(cin , s1);
getline(cin , s2);
lena = s1.length();
lenb = s2.length();
if(strcmp(s1.c_str() , s2.c_str()) == 0)
{
cout << 0;
return 0;
}
if((lena < lenb || lena == lenb) && strcmp(s1.c_str() , s2.c_str()) < 0)
{
cout << "-";
s3 = s1;
s1 = s2;
s2 = s3;
}
for(int i = 1 ; i <= lena ; i++)
{
a[i] = s1[lena - i] - '0';
}
for(int i = 1 ; i <= lenb ; i++)
{
b[i] = s2[lenb - i] - '0';
}
for(int i = 1 ; i <= lena ; i++)
{
if(a[i] < b[i])
{
a[i + 1]--;
a[i] += 10;
}
a[i] -= b[i];
}
while(a[lena] == 0 && lena > 1)
{
lena--;
}
for(int i = lena ; i >= 1 ; i--)
{
cout << a[i];
}
return 0;
}