ASP.NET的FileUpload控件默认是不支持服务端的onchange事件的，此时可以用一种变通的方法来实现这一功能。
这就需要借用客户端的onchange事件，调用__doPostBack方法来用LinkButton的OnClick事件模拟一个事件触发的过程，具体代码如下：
客户端：
<asp:FileUpload ID="fuPhoto" onchange="javascript:__doPostBack('lbUploadPhoto','')" runat="server" ToolTip="选择图片" />
<asp:LinkButton ID="lbUploadPhoto" runat="server" OnClick="lbUploadPhoto_Click"></asp:LinkButton>
后台代码：
//自动上传事件protected void lbUploadPhoto_Click(object sender, EventArgs e)
{fileUpload();}//从控件上传文件public void fileUpload()
{if (fuPhoto.PostedFile != null && fuPhoto.PostedFile.ContentLength > 0)
{string ext = System.IO.Path.GetExtension(fuPhoto.PostedFile.FileName).ToLower();
if (ext != ".jpg" && ext != ".jepg" && ext != ".bmp" && ext != ".gif")
{return;
}string filename = "Image_" + DateTime.Now.ToString("yyyyMMddHHmmss") + ext;
string path = "./UploadPhoto/" + filename;
fuPhoto.PostedFile.SaveAs(Server.MapPath(path));Response.Redirect("ImageCut.aspx?Picurl=" + Server.UrlEncode(path));
}else{//do some thing;}}