Description
Statements
Optical Character Recognition (OCR) is one of the most famous fields of Artificial Intelligence. The main purpose of OCR is to recognize printed text (or handwriting) and convert it to the machine encoded-text. You may have seen similar applications in your smartphone: you use your camera to take a photo that contains text, then, the text is translated or saved in PDF, for example. In this problem we deal with a very limited case of OCR. You have a scanned character which is either ‘0’ (number zero) or ‘8’ (number eight) and you have to decide what number it is. The input will be an image that contains exactly one character (It is guaranteed that this character is either ‘0’ or ‘8’). The image has 2 colors: white (represented with dot ‘.’) and black (represented with asterisk ‘*’). For simplicity, the borders of the image are always white. It’s also guaranteed that black lines inside the image are either vertical or horizontal. So you may safely assume that the shapes of ‘0’ and ‘8’ inside the image are the same as their shapes in digital clocks. However, they might be stretched or not positioned in the center of the image.
Input
The first line will be the number of test cases T (T<100). Each test case starts with two positive integers (n,m) denoting the dimensions of the image. (n,m < 20). Each of the following n lines contains m values which represent the image.
Output
For each test case, print one line which contains the number of the test case, and the recognition result: ‘Zero’ or ‘Eight’. See the samples and follow the output format.
Sample Input
3
8 10
..........
..*****...
..*...*...
..*...*...
..*****...
..*...*...
..*****...
..........
6 10
..........
..*****...
..*...*...
..*...*...
..*****...
..........
10 7
.......
.......
.......
.......
..****.
..*..*.
..****.
..*..*.
..****.
.......
Case 1: Eight
Case 2: Zero
Case 3: Eight
/*
给你一个字符矩阵让你判断里面*组成的团是8还是0 只需要判断有几条横杠就行了，三条就是8，两条就是0
*/
#include<stdio.h>
#include<iostream>
#include<algorithm>
#include<string.h>
#include<vector>
#define N 25
using namespace std;
int main()
{
//freopen("in.txt","r",stdin);
int t,n,m;
char ch[N][N];
scanf("%d",&t);
for(int l=;l<=t;l++)
{
int s=;
scanf("%d%d",&n,&m);
getchar();
for(int i=;i<n;i++)
{
scanf("%s",&ch[i]);
for(int j=;j<m;j++)
{
if(ch[i][j]=='*'&&ch[i][j+]=='*'&&ch[i][j+]=='*')
{
s++;
break;
}
}
}
//cout<<s<<endl;
if(s>)
printf("Case %d: Eight\n",l);
else
printf("Case %d: Zero\n",l);
}
return ;
}